The only thing that mkes this question inconvenient is that it uses a mixture of units ... speed in km/hr, and acceleration in m/s². You can't directly mash those together.
What's the speed when we express it in m/s ?
Speed = (90 km/hr) · (1,000 m/km) · (1 hr/3,600 sec)
Speed = (90 · 1,000 · 1 / 3,600) · (km-m-hr / hr-km-sec)
Speed = 25 m/s
OK great !
-- The car is traveling at 25 m/s when the brakes are applied.
-- The brakes slow it down by 0.5 m/s every second.
-- So it takes (25/0.5) = 50 seconds to stop the car.
-- During that time, the car's average speed is (1/2)·(25m/s + 0) = 12.5 m/s .
-- Moving at an average speed of 12.5 m/s for 50 sec, the car travels
(12.5 m/s) · (50 s) = <em>625 meters</em>
Answer:
Yes, it can can be completed adiabatically
Explanation:
To solve the problem we will resort to the theory of thermodynamics,
It is necessary to develop this problem to resort to the A-11E tables in English Units for R134a (since the problem requires it, if it were SI just to change to that table)
State 1 indicates that the refrigerant is at 60 ° F,
In the first table (attached image of the value taken) the value of the entropy is
For State 2 the refrigerant is at 50% quality and at a pressure of
In table 2 of the refrigerant (for the pressure values) we perform the reading and we have to
We know that,
The change in enthalpy would be given by
<em>The change in enthalpy is positive, so the process can be completed adiabatically</em>
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