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tigry1 [53]
3 years ago
8

5. If you designed a part with an overall width dimension of 1.250 inches and printed it on the same 3D printer using the same f

ilament, what would you predict the width of the printed part would measure?
6. If the width of your part had to measure between 1.220 inches and 1.255 inches to operate properly, would you adjust the width dimension of your CAD model to improve the chances of the 3D-printed model being within these limits? Explain your reasoning.

Engineering
2 answers:
vampirchik [111]3 years ago
5 0

Answer:

let us start by stating the definitions of Time series data and Cross sectional data. TIME SERIES DATA: The data which is collected chronologically over time is known as time series data.

sleet_krkn [62]3 years ago
3 0

Answer:

hu22 54=52222222222222

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Read 2 more answers
2–25 Consider a medium in which the heat conduction equation is given in its simplest form as
barxatty [35]

Answer:

d) Is the thermal conductivity of the medium constant or variable.

Explanation:

As we know that

Heat equation with heat generation at unsteady state and with constant thermal conductivity given as

\dfrac{d^2T}{dx^2}+\dfrac{d^2T}{dy^2}+\dfrac{d^2T}{dz^2}+\dfrac{\dot{q}_g}{K}=\dfrac{1}{\alpha }\dfrac{dT}{dt}

With out heat generation

\dfrac{d^2T}{dx^2}+\dfrac{d^2T}{dy^2}+\dfrac{d^2T}{dz^2}=\dfrac{1}{\alpha }\dfrac{dT}{dt}

In 2 -D with out heat generation with constant thermal conductivity

\dfrac{d^2T}{dx^2}+\dfrac{d^2T}{dy^2}=\dfrac{1}{\alpha }\dfrac{dT}{dt}

Given equation

\dfrac{d^2T}{dx^2}+\dfrac{d^2T}{dy^2}=\dfrac{1}{a }\dfrac{dT}{dt}

So we can say that this is the case of  with out heat generation ,unsteady state and with constant thermal conductivity.

So the option d is correct.

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