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3 years ago

You must find happiness right where you are lyrics

Chemistry

1 answer:

Vlad [161]3 years ago

3 0

Answer:

I'm guessing this is for "Where you are" from Moana as it's the only song I could find that goes <em>"You must find happiness where you are".</em>

Lyrics:

Moana, make way, make way

Moana, it's time you knew

The village of Motunui is

All you need

The dancers are practicing

They dance to an ancient song

(Who needs a new song? This old one's all we need)

This tradition is our mission

And Moana, there's so much to do (make way)

Don't trip on the taro root

That's all you need

We share everything we make (we make)

We joke and we weave our baskets

The fishermen come back from the sea

I wanna see

Don't walk away

Moana, stay on the ground now

Our people will need a chief

And there you are

There comes a day

When you're gonna look around

And realize happiness is

Where you are

Consider the coconut (the what?)

Consider its tree

We use each part of the coconut

That's all we need

We make our nets from the fibers

The water is sweet inside

We use the leaves to build fires

We cook up the meat inside

Consider the coconuts

The trunks and the leaves

The island gives us what we need

And no one leaves

That's right, we stay

We're safe and we're well provided

And when we look to the future

There you are

You'll be okay

In time you'll learn just as I did

You must find happiness right

Where you are

I like to dance with the water

The undertow and the waves

The water is mischievous

I like how it misbehaves

The village may think I'm crazy

Or say that I drift too far

But once you know what you like, well

There you are

You are your father's daughter

Stubbornness and pride

Mind what he says but remember

You may hear a voice inside

And if the voice starts to whisper

To follow the farthest star

Moana, that voice inside is

Who you are

We make our nets from the fibers

The water is sweet inside

We use the leaves to build fires

And cook up the meat inside

The village believes in us

The village believes

The island gives us what we need

And no one leaves

So here I'll stay

My home, my people beside me

And when I think of tomorrow

There we are

I'll lead the way

I'll have my people to guide me

We'll build our future together

Where we are

'Cause every path leads you back to

Where you are

You can find happiness right

Where you are

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Find the ph of of 100 ml of an aqueous 0.43m baoh2 solution

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Answer is: pH of barium hydroxide is 13.935.
Chemical dissociation of barium hydroxide in water:
Ba(OH)₂(aq) → Ba²⁺(aq) + 2OH⁻(aq).
c(Ba(OH)₂) = 0.43 M.
V(Ba(OH)₂) = 100 mL ÷ 1000 mL/L = 0.1 L.
n(Ba(OH)₂) = 0.43 mol/L · 0.1 L.
n(Ba(OH)₂) = 0.043 mol.
From chemical reaction: n(Ba(OH)₂) : n(OH⁻) = 1 : 2.
n(OH⁻) = 0.086 mol.
c(OH⁻) = 0.86 mol/L.
pOH = -logc(OH⁻).
pOH = 0.065.
pH = 14 - 0.065 = 13.935.

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The Handbook of Chemistry and Physics gives solubilities of the following compounds in grams per 100 mL water. Because these com

Elanso [62]

Answer:

(a) $Ksp=4.50x10^{-7}$

(b) $Ksp=1.55x10^{-6}$

(d) $Ksp=1.05x10^{-22}$

Explanation:

Hello,

In this case, given the solubility of each salt, we can compute their molar solubilities by using the molar masses. Afterwards, by using the mole ratio between ions, we can compute the concentration of each dissolved and therefore the solubility product:

(a) $BaSeO_4(s)\rightleftharpoons Ba^{2+}(aq)+SeO_4^{2-}(aq)$

$Molar\ solubility=\frac{0.0188g}{100mL} *\frac{1mol}{280.3g}*\frac{1000mL}{1L}=6.7x10^{-4}\frac{mol}{L}$

In such a way, as barium and selenate ions are in 1:1 molar ratio, they have the same concentration, for which the solubility product turns out:

$Ksp=[Ba^{2+}][SeO_4^{2-}]=(6.7x10^{-4}\frac{mol}{L} )^2\\\\Ksp=4.50x10^{-7}$

(B) $Ba(BrO_3)_2(s)\rightleftharpoons Ba^{2+}(aq)+2BrO_3^{-}(aq)$

$Molar\ solubility=\frac{0.30g}{100mL} *\frac{1mol}{411.15g}*\frac{1000mL}{1L}=7.30x10^{-3}\frac{mol}{L}$

In such a way, as barium and bromate ions are in 1:2 molar ratio, bromate ions have twice the concentration of barium ions, for which the solubility product turns out:

$Ksp=[Ba^{2+}][BrO_3^-]^2=(7.30x10^{-3}\frac{mol}{L})(3.65x10^{-3}\frac{mol}{L})^2\\\\Ksp=1.55x10^{-6}$

$Molar\ solubility=\frac{0.038g}{100mL} *\frac{1mol}{289.35g}*\frac{1000mL}{1L}=1.31x10^{-4}\frac{mol}{L}$

In such a way, as ammonium, magnesium and arsenate ions are in 1:1:1 molar ratio, they have the same concentrations, for which the solubility product turns out:

$Ksp=[NH_4^+][Mg^{2+}][AsO_4^{3-}]^2=(1.31x10^{-4}\frac{mol}{L})^3\\\\Ksp=2.27x10^{-12}$

(D) $La_2(MoOs)_3(s)\rightleftharpoons 2La^{3+}(aq)+3MoOs^{2-}(aq)$

$Molar\ solubility=\frac{0.00179g}{100mL} *\frac{1mol}{1136.38g}*\frac{1000mL}{1L}=1.58x10^{-5}\frac{mol}{L}$

In such a way, as the involved ions are in 2:3 molar ratio, La ion is twice the molar solubility and MoOs ion is three times it, for which the solubility product turns out:

$Ksp=[La^{3+}]^2[MoOs^{-2}]^3=(2*1.58x10^{-5}\frac{mol}{L})^2(3*1.58x10^{-5}\frac{mol}{L})^3\\\\Ksp=1.05x10^{-22}$

Best regards.

7 0

3 years ago