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jasenka [17]
3 years ago
12

If 97.7 ml of silver nitrate solution reacts with excess potassium chloride solution to yield 0.326 g of precipitate, what is th

e molarity of silver ion in the original solution?
Chemistry
1 answer:
BlackZzzverrR [31]3 years ago
4 0

The complete balanced chemical reaction is written as:

AgNO3 + KCl ---> AgCl + KNO3 

where AgCl is our precipitate

 

So calculating for moles of AgCl produced: MM AgCl = 143.5 g/mol

moles AgCl = 0.326 g / (143.5 g/mol) = 2.27 x 10^-3 mol

we see that there is 1 mole of Ag per 1 mole of AgCl so:

moles Ag = 2.27 x 10^-3 mol

 

The molarity is simply the ratio of number of moles over volume in Liters, therefore:

Molarity = 2.27 x 10^-3 mol / 0.0977 L

<span>Molarity = 0.0233 M</span>

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Estimate the percent ionic character of the co bond. (note that the electronegativity of c is 2.5 and that of o is 3.5.)
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From the calcuation, the percent ionic character of the bond is  70%

<h3>What is percent ionic character?</h3>

The term percent ionic character has to do with the degree of ionic bonding that is contained in a compound. It can be estimated from the electronegativity of each element.

We can use the formula; 100(1 - e^(-ΔEN² / 4))

EN = χB − χA * 100/1

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100(1 - e^(-1)^2/4)

= 70%

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An ideal monatomic gas at 300 K expands adiabatically to twice its initial volume. Assume that the process is also quasistatic.
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Answer:

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In this problem, we need to use a gas law that relates temperature to volume. The gas law to use here is the Charles’ law.

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