Answer:
Yes
Explanation:
Momentum before collision = momentum after collision
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
The cars stick together after the collision, so they have the same final velocity.
m₁u₁ + m₂u₂ = m₁v + m₂v
m₁u₁ + m₂u₂ = (m₁ + m₂)v
Plug in values and solve (take Jay Z's direction to be positive):
(1100) (-20) + (1475) u₂ = (1100 + 1475) (7)
u₂ = 27.1 m/s
Yes, Jay Z was speeding.
Assuming your two trolleys stick together after the collision, your momentum equation would be M1V1+M2V2=(M1+M2)V3 and since V2 is 0, then 2x2=(2+2)V3, thereore the final velocity would be 1, wich would make the final momentum 4
Without knowing anything about their magnitudes or directions, the only thing you can always say about thier combination is that it's the "net force" on the object.
Answer:
A <em>concave</em><em> </em><em>lens</em><em> </em><em>is</em><em> </em><em>thinner</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>cen</em><em>ter</em><em> </em><em>and </em><em>thick</em><em>er</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>edges</em><em> </em><em>while</em><em> </em><em>a</em><em> </em><em>convex </em><em>lens </em><em>is</em><em> </em><em>thicker</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>centre</em><em> </em><em>and</em><em> </em><em>thinner</em><em> </em><em>at</em><em> </em><em>the</em><em> edges</em><em>.</em>