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vagabundo [1.1K]
3 years ago
13

A 113 kg man sits on the stern of a 6.3 m long boat. The prow of the

Physics
1 answer:
Usimov [2.4K]3 years ago
3 0

Answer:

m = 105.37 kg

Explanation:

We are given;

Mass of man; m = 113 kg

Length of boat = 6.3m

Now, The position of the center of mass will not change during the motion of the man.

Thus,

X_g,i = X_g,f

So,

[113(6.3) + ma]/(113 + m) = [113(3.26) + m(a +3.26)]/(113 + m)

113 + m will cancel on both sides to give;

113(6.3) + ma = [113(3.26) + m(a +3.26)]

711.9 + ma = 368.38 + ma + 3.26m

ma will cancel out to give;

711.9 - 368.38 = 3.26m

343.52/3.26 = m

m = 105.37 kg

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An airplane flies with a velocity of 750. kilometers
viktelen [127]

Answer:

650 km/hr

Explanation:

Draw a right triangle from (0.0) (Point A) down 30 degrees and to the right for a length of 750 (Point B).  Then draw a line from B up to the x axis to make a right angle (Point C).  Use the cosine function to find line AC, the vector portion of AB that lies of the x (East) axis.  Cosine(30)= Adjacent/Hypotenuse.

Cos(30) = AC/750

750*(cos(30)) = AC

AC = 649.5 km/hr

5 0
2 years ago
Read 2 more answers
A piece of bismuth with a mass of 4.06 g 4.06 g gains 423 J 423 J of heat. If the specific heat of bismuth is 0.123 J / ( g ° C
Sholpan [36]

Answer: 846°C

Explanation:

The quantity of Heat Energy (Q) required to heat bismuth depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that:

Q = 423 joules

Mass of bismuth = 4.06g

C = 0.123 J/(g°C)

Φ = ?

Then, Q = MCΦ

423 J = 4.06g x 0.123 J/(g°C) x Φ

423 J = 0.5J/°C x Φ

Φ = (423J/ 0.5g°C)

Φ = 846°C

Thus, the change in temperature of the sample is 846°C

4 0
3 years ago
While taking off from an aircraft carrier, a jet starting from rest accelerates uniformly to a final speed of 40. meters per sec
mariarad [96]

The acceleration of the jet is 11.4 m/s^2

Explanation:

Since the jet motion is a uniformly accelerated motion (=constant acceleration), we can use the following suvat equation:

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

For the jet in this problem, we have

u = 0 (it starts from rest)

v = 40 m/s (final velocity)

s = 70 m (length of the runway)

Solving for a, we find the acceleration:

a=\frac{v-u}{t}=\frac{40^2-0}{2(70)}=11.4 m/s^2

Learn more about acceleration:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

5 0
3 years ago
If an object that weighs 20 N is lifted from the ground to a
Radda [10]

Answer:

false 20 n x 0.32 m = 6.4 J

3 0
3 years ago
A dogsled team has a total momentum of 1710 kg•m/s. If the team has a total mass of 450 kg, what is its speed?
HACTEHA [7]

Answer:

3.8 m/s

Explanation:

Momentum is the product of mass and velocity hence

Momentum=mv where m is mass and v is the velocity of an object

Making v the subject of the formula then

v=\frac {momentum}{m}

Substituting 1710 kgm/s for momentum and 450 Kg for mass we obtain

v=\frac {1710 Kgm/s}{450 Kg}=3.8 m/s

Hence the speed of dogsled team is 3.8 m/s

7 0
3 years ago
Read 2 more answers
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