Answer:
E = hf
E = hc/lamda
where E-energy,
h-planck's constant (6.62 x 10^-34 Js)
f- frequency ( f = c/lamda)
c-velocity of light ( 3 x 10^8 m/s)
lamda- wavelength
you can this formula to solve all the 4 questions.
Answer:
The answer is option b.
Explanation:
Amplitude is the distance apart each wave is.
Its a covalent bond for this q
Yes the answer is a , kinetic energy
