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3 years ago

13

Một xe máy đang đi với v = 50,4 km/h bỗng người lái xe thấy có ổ gà trước mắt cách xe 24,5 m.Người ấy phanh gấp và xe đến ổ gà t

hì dừng lại. Gia tốc của xe là

1 answer:

Finger [1]3 years ago

3 0

Answer:

<h3>эмне, кечиресиз айым, бирок мен сиздин тилиңизди түшүнбөй</h3>

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What volume of h2 gas (in l), measured at 756 mmhg and 90 ∘c, is required to synthesize 23.0 g ch3oh?

Naddika [18.5K]

First let us calculate for the moles of CH3OH formed:

moles CH3OH = 23 g / (32 g / mol) = 0.71875 mol

We see that there are 2 moles of H2 per mole of CH3OH, so:

moles H2 = 0.71875 mol * 2 = 1.4375 mol

Assuming ideal gas behaviour, we use the formula:

PV = nRT

V = nRT / P

V = 1.4375 mol * (62.36367 L mmHg / mol K) * (90 + 237.15 K) / 756 mm Hg

<span>V = 43.06 Liters</span>

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3 years ago

If a compound forms by ionic bonding, which is not true?

MrRa [10]

Answer:is deez nut;D

Explanation:

because u gay...

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3 years ago

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The Mars Curiosity rover was required to land on the surface of Mars with a velocity of 1 m/s. Given the mass of the landing veh

Aliun [14]

Answer:

The value is $A = 39315 \ m^2$

Explanation:

From the question we are told that

The velocity which the rover is suppose to land with is $v = 1 \ m/s$

The mass of the rover and the parachute is $m = 2270 \ kg$

The drag coefficient is $C__{D}} = 0.5$

The atmospheric density of Earth is $\rho = 1.2 \ kg/m^3$

The acceleration due to gravity in Mars is $g_m = 3.689 \ m/s^2$

Generally the Mars atmosphere density is mathematically represented as

$\rho_m = 0.71 * \rho$

=> $\rho_m = 0.71 * 1.2$

=> $\rho_m = 0.852 \ kg/m^3$

Generally the drag force on the rover and the parachute is mathematically represented as

$F__{D}} = m * g_{m}$

=> $F__{D}} = 2270 * 3.689$

=> $F__{D}} = 8374 \ N$

Gnerally this drag force is mathematically represented as

$F__{D}} = C__{D}} * A * \frac{\rho_m * v^2 }{2}$

Here A is the frontal area

So

$A = \frac{2 * F__D }{ C__D} * \rho_m * v^2 }$

=> $A = \frac{2 * 8374 }{ 0.5 * 0.852 * 1 ^2 }$

=> $A = 39315 \ m^2$

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3 years ago

A wire along the z axis carries a current of 6.8 A in the z direction Find the magnitude and direction of the force exerted on a

Alexeev081 [22]

Answer:

Force is 14.93N along positive y axis.

Explanation:

We know that force 'F' on a current carrying conductor placed in a magnetic field of intensity B is given by

$\overrightarrow{F}=\overrightarrow{Il}\times \overrightarrow{B}$

where L is the length of the conductor

Applying values in the equation we have force F =

$\overrightarrow{F}=6.8\times 6.1\widehat{k}\times 0.36\widehat{i}\\\\\overrightarrow{F}=41.48\widehat{k}\times 0.36\widehat{i}\\\\\therefore \overrightarrow{F}=14.93N\widehat{j}$

Thus force is 14.93N along positive y axis.

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3 years ago

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timurjin [86]

I think its true because they are a soft solid that can be broken down into a liquid... Hope this helps in any way :3

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3 years ago

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