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Sonbull [250]
2 years ago
8

A 1.5 m x1.5 m square footing is supported by a soil deposit that contains a 16.5 m thick saturated clay layer followed by the b

edrock. The clay has μs = 0.50 and Es = 5,000 kN/m2 . The footing base is at 1.5 m below the ground surface. Determine the maximum vertical central column load so that the elastic settlement of the footing will not exceed 50.0 mm. If the square footing is replaced by a 1.2 m wide wall footing with all other conditions remaining the same.
Required:
What will be the elastic settlement under the same footing pressure?
Engineering
1 answer:
iren [92.7K]2 years ago
7 0

Answer:

somewhere around 34.2223 meters thick but that's what I am estimating.

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Do all websites use the same coding to create?
Sonbull [250]

Answer:

yes.

Explanation:

because all websites use coding

6 0
3 years ago
How can you evaluate whether the slope of the dependent variable with an independent variable is the same for each level of the
s2008m [1.1K]

Answer:

By running multiple regression with dummy variables

Explanation:

A dummy variable is a variable that takes on the value 1 or 0. Dummy variables are also called binary

variables. Multiple regression expresses a dependent, or response, variable as a linear

function of two or more independent variables. The slope is the change in the response variable. Therefore, we have to run a multiple regression analysis when the variables are measured in the same measurement.The number of dummy variables you will need to capture a categorical variable

will be one less than the number of categories. When there is no obvious order to the categories or when there are three or more categories and differences between them are not all assumed to be equal, such variables need to be coded as dummy variables for inclusion into a regression model.

3 0
3 years ago
Air enters a turbine with a stagnation pressure of 900 kPa and a stagnation temperature of 658K, and it is expanded to a stagnat
bezimeni [28]

Answer:

12.332 KW

The positive sign indicates work done by the system ( Turbine )

Explanation:

Stagnation pressure( P1 ) = 900 kPa

Stagnation temperature ( T1 ) = 658K

Expanded stagnation pressure ( P2 ) = 100 kPa

Expansion process is  Isentropic, also assume steady state condition

mass flow rate ( m ) = 0.04 kg/s

<u>Calculate the Turbine power </u>

Assuming a steady state condition

( p1 / p2 )^(r-1/r)  = ( T1 / T2 )

= (900 / 100)^(1.4-1/1.4) = ( 658 / T2 )

=  ( 9 )^0.285 = 658 / T2

∴ T2 = 351.22 K

Finally Turbine Power / power developed can be calculated as

Wt = mCp ( T1 - T2 )

    = 0.04 * 1.005 ( 658 - 351.22 )

    = 12.332 KW

The positive sign indicates work done by the system ( Turbine )

6 0
2 years ago
An ideal gas undergoes two processes: one frictionless and the other not. In both the cases, the gas is initially at 200 ℉ and 1
Zarrin [17]

Answer:

The process which has friction

Explanation:

The entropy is simply the change in the state of the things or the molecules in the system. It is simply the change in the energy of the system with a focus on the atoms in the system. This is also known as the internal energy of the system and is given the symbol, G. The friction contributes to the change in the energy of the system. This is because friction generates another form of energy - that is heat energy. This energy causes the internal temperature id the system to increase. Hence the greater change in the temperature.

6 0
3 years ago
Read 2 more answers
To become familiar with the general equations of plane strain used for determining in-plane principal strain, maximum in-plane s
lukranit [14]

Answer:

a) -1.46 x 10∧-5, 1.445x 10∧-4, -6.355 x 10∧-4

b) 3.926 x 10∧-4, -2.626 x 10∧-4

c) 6.552 x 10∧-4, 6.5 x 10∧-5

Explanation:

a) -1.46 x 10∧-5, 1.445x 10∧-4, -6.355 x 10∧-4

b) 3.926 x 10∧-4, -2.626 x 10∧-4

c) 6.552 x 10∧-4, 6.5 x 10∧-5

The explanation is shown in the attachment. I hope i have been able to help.

3 0
3 years ago
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