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Zielflug [23.3K]
3 years ago
8

The elements present in common salt are ..

Chemistry
2 answers:
vagabundo [1.1K]3 years ago
7 0

Answer:   sodium  and chloride

Explanation:

marin [14]3 years ago
5 0

Answer:

Hello, There!

I'm glad to help!

The molecular formula of common salt is NaCI

And the elements present are

Sodium (Na)

Chlorine (CI)

Explanation:

<u><em>A pure substance that consists of only the same kind of atoms is called an element whereas two or more elements combine to form a compound. </em></u>

<u><em /></u>

<u><em /></u>

<em>Therefore, I hope this Helps!</em>

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Abbreviation for mole
Sedbober [7]

Answer:

Maybe mol

Explanation:

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3 years ago
Deterioration of buildings, bridges, and other structures through the rusting of iron costs millions of dollars a day. The actua
GrogVix [38]

The value of ∆H when 0.250kg of iron rusts is -1.846 × 10³kJ.

The rust forms when 4.85X10³ kJ of heat is released is 888.916 g.

<h3>Chemical reaction:</h3>

4 Fe + 3O2 ------ 2Fe2O3

∆H = -1.65×10³kJ

A) Given,

mass of iron = 0.250kg = 250 g

<h3>Calculation of number of moles</h3>

moles = given mass/ molar mass

= 250/ 55.85 g/mol.

= 4.476 mol

As we know that,

For the rusting of 4 moles of Fe, ∆H = -1.65×10³kJ

For the rusting of 4.476 moles of Fe ∆H required can be calculated as

-1.65×10³kJ × 4.476 mol/ 4mol

∆H required = -1.846 × 10³kJ

Now,

when 2 mol of Fe2O3 formed, ∆H = - 1.65×10³kJ

It can be said that,

-1.65×10³kJ energy released when 2 mol of Fe2O3 formed

So, -4.6 × 10³kJ energy released when 2 mol of Fe2O3 formed

= 2 × -4.6 × 10³kJ / -1.65×10³kJ

= 5.57 mol of Fe2O3 formed

Now,

mass of Fe2O3 formed = 5.57 mol × 159.59 g/mol

= 888.916 g

Thus, we calculated that the rust forms when 4.85X10³ kJ of heat is released is 888.916 g. and the value of ∆H when 0.250kg of iron rusts is -1.846 × 10³kJ.

learn more about ∆H:

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DISCLAIMER:

The given question is incomplete. Below is the complete question

QUESTION:

Deterioration of buildings, bridges, and other structures through the rusting of iron costs millions of dollars a day. The actual process requires water, but a simplified equation is 4Fe(s) + 3O₂(g) → 2Fe₂O₃(s) ΔH = -1.65×10³kJ

a) What is the ∆H when 0.250kg iron rusts.

(b) How much rust forms when 4.85X10³ kJ of heat is released?

7 0
2 years ago
When you transferred the hot metal from the boiling water and into the calorimeter (coffee cup), if the thermometer touched the
sergey [27]

When you transferred the hot metal from the boiling water and into the calorimeter,  The effect will be

  • Change in temp is positive
  • Temp of metal V, dT=-ve
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This is further explained below.

<h3>What is the Specific heat of the metal?</h3>

a )Since the metal of the cup is hot and the water inside is cold, the water's temperature will rise as heat is transferred from the metal to the liquid.

Change in temp is positive

b)

Due to (a), heat is lost from the food to the water in the cup, lowering the metal's temperature.

Temp of metal V, dT=-ve

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7 0
2 years ago
Read 2 more answers
The yttrium- nuclide radioactively decays by electron capture. Write a balanced nuclear chemical equation that describes this pr
evablogger [386]

Answer:

See explanation and image attached

Explanation:

Yttrium has many isotopes, the lowest mass number of Yttrium  is 89Y.

Recall that electron capture converts an electron into a proton and then into a neutron with a consequent emission of a neutrino (v).

In electron capture, the mass number of the daughter nucleus remains the same as that of the parent nucleus while the atomic number of the daughter nucleus is less than that of the parent by one unit.

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Suppose you have an Avogadro's number of nitrogen atoms. How many grams does this represent? Enter your answer to one decimal pl
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Answer:

2.3 x 10-23 g.

Explanation:

The mass of a single atom is the mass number, 14, is the mass in grams of one mole of carbon.

One mole of Nitrogen atom is 6.022 x 1023 atoms (Avogadro's number). This can then used to convert a nitogen atom to grams by the ratio:

mass of 1 atom / 1 atom = mass of a mole of atoms / 6.022 x 10^23 atoms.

mass of 1 atom = mass of a mole of atoms / 6.022 x 1023

mass of 1 N atom = 14 / 6.022 x 10^23 N atoms

mass of 1 N atom = 2.325 x 10^-23 g

The mass of a single Nitrogen atom is 2.325 x 10-23 g.

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3 years ago
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