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Tasya [4]
2 years ago
10

An autographed baseball rolls off of a 0.99 m high desk and strikes the floor 0.34 m away

Physics
2 answers:
Sever21 [200]2 years ago
8 0

why does the baseball have to be autographed?

il63 [147K]2 years ago
5 0

Answer:

Below

Explanation:

First, we need to find the time of flight of this projectile :

     t=\sqrt{\frac{2dy}{g} }

     t =\sqrt{\frac{2(0.99)}{9.81}

     t =\sqrt{\frac{1.98}{9.81}

     t =\sqrt{0.20183486238}

     t = 0.448489506 seconds

Now we can use this formula to find the initial horizontal velocity :

     Dhorizontal = Vhorizontal (time)

     0.34 m = Vx(0.448489506) \\0.76m/s^2 = Vx

Therefore the initial velocity of the baseball was 0.76 m/s^2 [Forward]

Hope this helps! Best of luck <3

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Rank the objects below in order from smallest to largest, where 1 is the smallest and 5 is the largest. local group of galaxies
sasho [114]
1. earth
2. solar system
3. milky way galaxy
4. local group of galaxies
5. universe
4 0
3 years ago
Two identical conducting spheres are placed 80.0 cm apart. One is given a charge of 5.8 C and the other is given a charge of 6.4
Zepler [3.9K]

Answer: 5.214(10)^{11} N

Explanation:

According to <u>Coulomb's Law:</u>  

<em>"The electrostatic force F_{E} between two point charges q_{1} and q_{2} is proportional to the product of the charges and inversely proportional to the square of the distance d that separates them, and has the direction of the line that joins them".</em>

<em />

Mathematically this law is written as:

F_{E}=K\frac{q_{1}.q_{2}}{d^{2}}  

Where:

F_{E}  is the electrostatic force

K=8.99(10)^{9} Nm^{2}/C^{2} is the Coulomb's constant  

q_{1}=5.8 C and q_{2}=6.4 C are the electric charges

d=80 cm \frac{1 m}{100 cm}=0.8 m is the separation distance between the charges

Solving:

F_{E}=8.99(10)^{9} Nm^{2}/C^{2}\frac{(5.8 C)(6.4 C)}{(0.8 m)^{2}}  

F_{E}=5.214(10)^{11} N    

7 0
3 years ago
A 40.0 -kg box initially at rest is pushed 5.00 m along a rough, horizontal floor with a constant applied horizontal force of 13
Irina18 [472]

The work done by the gravitational force = 0

Given the mass of the box = 40 kg

The box is initially at rest.

Distance moved by the applied force = 5m

Force applied = 130 N

Co-efficient of friction between the box and floor = 0.3

The box is moved only in the horizontal direction by the applied force.

Gravitational force is applied in a direction perpendicular to the applied force. hence it doesn't do any work on the box.

Therefore, the work done by the gravitational force is zero.

Learn more about the gravitational force at brainly.com/question/862529

#SPJ4

3 0
2 years ago
A soft drink (mostly water) flows in a pipe at a beverage plant with a mass flow rate that would fill 220 0.355 - L cans per min
Yuki888 [10]

Answer:

A. To find the mass flow rate.

We use= 220 x 0.355/ 60

= 1.3kg/s

B. Volume flowrate is = mass flowrate / density

But density is 1000kg/m³

= 1.3kg/s/ 1000kg/m³

= 0.0013m³/s

C. Flow speead at 1

= 0.0013m³/s / (2 x 10-2m)²

= 6.5m/s

D.flow speed at 2

0.0013m³/s / (8x 10-2m)²

=1.63m/s

E. Gauge pressure at point 1

= 152+ 1/1000 ( 1.63)²- 6.5² + 1000( 9.8) ( 0-1.35)

= 119kpa

7 0
3 years ago
A student made the claim that a 4 gram paintball fired from a paintball gun at 90 m/s could have about the same kinetic energy a
Fiesta28 [93]

Answer:

I do agree with the student. Because imagene you have a tissue and a stick. And you throw them at the same speed , the stick will go farther because it' s heavier but the tissue would just blow around and not go forward because it is not heavy enought.

Explanation:

Hope this is correct have a terrific day.

5 0
3 years ago
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