Scientists think the earliest version of the eye was formed in unicellular organisms, who had something called 'eyespots'. These eyespots were made up of patches of photoreceptor proteins that were sensitive to light. ... Over time, the unicellular creature would evolve, and its eyespot evolved along with it.
Answer:
You are correct, it is (3) the ball is in motion as it rolls down the slope.
Explanation:
For number 1 it would make sense because how would the student be in motion if he is just standing there throwing the ball down the slope, not himself.
For number 2 still wouldn't make so much sense since we are talking about the ball being in motion not the student.
For number 3 it seems the most reasonable because the ball is in motion as it is rolling down the slope.
For number 4 it doesn't make sense for a ball to lose its shape just by rolling, also even if you're like: "oh, but what if its leaking air or has a hole??" well easy then. It STILL wouldn't matter because in the sentence it never specifies it has a "hole" or is "leaking air" therefore this answer is wrong.
YOUR ANSWER IS number 3.
Quasi frequency = 4√6
Quasi period = π√6/12
t ≈ 0.4045
<u>Explanation:</u>
Given:
Mass, m = 20g
τ = 400 dyn.s/cm
k = 3920
u(0) = 2
u'(0) = 0
General differential equation:
mu" + τu' + ku = 0
Replacing the variables with the known value:
20u" + 400u' + 3920u = 0
Divide each side by 20
u" + 20u' + 196u = 0
Determining the characteristic equation by replacing y" with r², y' with r and y with 1 in the differential equation.
r² + 20r + 196 = 0
Determining the roots:
r = -10 ± 4√6i
The general solution for two complex roots are:
y = c₁ eᵃt cosbt + c₂ eᵃt sinbt
with a the real part of the roots and b be the imaginary part of the roots.
Since, a = -10 and b = 4√6
u(t) = c₁e⁻¹⁰^t cos 4√6t + c₂e⁻¹⁰^t sin 4√6t
u(0) = 2
u'(0) = 0
(b)
Quasi frequency:
μ =
(c)
Quasi period:
T = 2π / μ
(d)
|u(t)| < 0.05 cm
u(t) = |2e⁻¹⁰^t cos 4√6t + 5√6/6 e⁻¹⁰^t sin 4√6t < 0.05
solving for t:
τ = t ≈ 0.4045
Answer:
a) 1.57, 1.61
B 1.91x10^8m/s , 1.86 x 10^8m/s
Explanation:
Ok we know that refractive index is given as = sin i/ sin r
And i is the angle of incidence in the air and r is angle of refraction in the glass,
So we can sa y
for red light n = sin75/sin38.1 = 1.57
and for violet, n =sin75/sin36.7 = 1.61
So
(a) 1.57, 1.61
(b) we know that
Refractive index n = c/v,
where c is speed off light in air and v is speed of light in glass,
So , v = c/n
for red light v = c/1.57 = 1.91 x 10^8 m/s
and for violet light, v = c/1.61 =
1.86 x 10^8 m/s