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adell [148]
2 years ago
12

The following best describes how an anthropogenic activity can increase ocean acidification?​

Physics
1 answer:
worty [1.4K]2 years ago
6 0

Answer:

Emissions from power plants that burn fossil fuels increase atmospheric carbon dioxide, which is absorbed by the ocean.

Explanation:

Fossil fuels are burnt in power plants in order to produce energy. These fossil fuels contain carbon. Combustion of these fossil fuels emits oxides of carbon into the atmosphere. The oxides of carbon are carbon II oxide and carbon dioxide.

Carbon dioxide can be absorbed by the ocean to form carbonic acid according to the reaction equation;

CO2(aq) + H2O(l) ------> H2CO3(aq)

This is an anthropogenic activity which increases ocean acidification.

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A train moves with a constant velocity for 15s for 155m. How fast is the train moving?
bonufazy [111]

Answer: 10.3m/s

Explanation:

In theory and for a constant velocity the physics expression states that:

Eq(1):  distance  = velocity times time <=> d = v*t    for v=constant.

If we solve Eq (1) for the velocity (v) we obtain:

Eq(2):  velocity  = distance divided by time <=> v = d/t

Substituting the known values for t=15s and d=155m we get:

v = 155 / 15 <=> v = 10.3

5 0
3 years ago
In just 0.30 s , you compress a spring (spring constant 5000 n/m ), which is initially at its equilibrium length, by 4.0 cm. par
Ierofanga [76]
The average power output is the ratio between the work done to compress the spring, W, and the time taken, t:
P= \frac{W}{t} (1)

The work done is equal to the elastic energy stored by the compressed spring:
W=U= \frac{1}{2}kx^2
where k=5000 N/m is the spring constant and x=4.0 cm=0.04 m is the compression of the spring. If we substitute the numbers, we find:
W= \frac{1}{2}(5000 N/m)(0.04 m)^2=4 J

And now we can use eq.(1) to calculate the average power output:
P= \frac{W}{t}= \frac{4 J}{0.30 s}  =13.3 W
7 0
3 years ago
A car is traveling at 100 km/h when the driver sees an accident 80 m ahead and slams on the brakes. what minimum constant decele
Effectus [21]
Assuming the driver starts slamming the brakes immediately, the car moves by uniformly decelerated motion, so we can use the following relationship
2aS = v_f^2 - v_i^2 (1)
where 
a is the deleceration
S is the distance covered after a time t
v_f is the velocity at time t
v_i=100 km/h = 27.8 m/s is the initial speed of the car

The accident is 80 m ahead of the car, so the minimum deceleration required to avoid the accident is the value of a such that S=80 m and v_f=0 (the car should stop exactly at S=80 m to avoid the accident). Using these data, we can solve  the equation (1) to find a:
a=- \frac{v_i^2}{2 S}= -\frac{(27.8 m/s)^2}{2 \cdot 80 m} =-4.83 m/s^2
And the negative sign means it is a deceleration.

4 0
3 years ago
A bottle dropped from a balloon reaches the ground in 20 s. determine the height of the balloon if (a) it was at rest in the air
romanna [79]
<span>a) 1960 m b) 960 m Assumptions. 1. Ignore air resistance. 2. Gravity is 9.80 m/s^2 For the situation where the balloon was stationary, the equation for the distance the bottle fell is d = 1/2 AT^2 d = 1/2 9.80 m/s^2 (20s)^2 d = 4.9 m/s^2 * 400 s^2 d = 4.9 * 400 m d = 1960 m For situation b, the equation is quite similar except we need to account for the initial velocity of the bottle. We can either assume that the acceleration for gravity is negative, or that the initial velocity is negative. We just need to make certain that the two effects (falling due to acceleration from gravity) and (climbing due to initial acceleration) counteract each other. So the formula becomes d = 1/2 9.80 m/s^2 (20s)^2 - 50 m/s * T d = 1/2 9.80 m/s^2 (20s)^2 - 50m/s *20s d = 4.9 m/s^2 * 400 s^2 - 1000 m d = 4.9 * 400 m - 1000 m d = 1960 m - 1000 m d = 960 m</span>
6 0
3 years ago
When you are ice skating, to get started, you push your stake backwards on the ice and, as a result, begin to move forward. whic
Flauer [41]

The law of motion that is being described in this scenario is Friction. Friction between the skate and the ice is what's moving the skater forward.

6 0
3 years ago
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