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Sindrei [870]
3 years ago
15

Si (IV) + CL2 --> SICLY O synthesis O decomposition O single displacement O double displacement O MgCl2 + NaOH --> Mg(OH)2

+ NaCl O synthesis O O decomposition single displacement O O double displacement​

Chemistry
1 answer:
Marta_Voda [28]3 years ago
8 0

Answer:

1. decomposition

2. double displacement

Explanation:

please mark it as a brain... ans...

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Explanation:

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3 years ago
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How many moles of SnF₂ will be produced along with 48 grams of H₂? *
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Answer: 24 moles of SnF_2 are produced.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

{\text{Moles of}  H_2}=\frac{48g}{2g/mol}=24moles

Sn+2HF\rightarrow SnF_2+H_2

According to stoichiometry :

1 mole of H_2 is accompanied with = 1 mole of SnF_2

Thus 24 moles of H_2  is accompanied with =\frac{1}{1}\times 24=24moles  of SnF_2

Thus 24 moles of SnF_2 are produced.

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3 years ago
Analysis of an ore of calcium shows that it contains 13.61 g calcium and 21.77 g oxygen in a 46.28-g sample. Calculate the perce
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Answer:

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The percent composition of an atom in a molecule is defined as 100 times the ratio between the mass of the atom and the mass of the molecule.

The mass of the molecule of the problem (Ore) is 46.28g. That means the percent composition of Calcium is:

13.61g / 46.28g * 100 = 29.41% of Calcium

And percent composition of Oxygen is:

21.77g / 46.28g * 100 = 47.04% of Oxygen

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