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Marina86 [1]
2 years ago
6

For the reaction shown, find the limiting reactant for each of the initial quantities of reactants.

Chemistry
1 answer:
Charra [1.4K]2 years ago
3 0

Answer:

heres the link of the answer

boldniwally.com

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A student listed the characteristics of chemical and nuclear reactions.
lidiya [134]

Answer:

D. It is a chemical reaction because the total mass remains the same when new substances are formed.

Explanation:

A chemical reaction is represented by a chemical equation which show the reactant and products. Reactants are written on left side of arrow while products are written on right side. The number of atoms are remain same however arrangement of atoms is different on both side.

For example:

6H₂O + 6CO₂ + energy  →   C₆H₁₂O₆ + 6O₂

it is known from balanced chemical equation that 6 moles of carbon dioxide react with the six moles of water and created one mole of glucose and six mole of oxygen. The number of atoms are same on both side however arrangement of atoms is different.

While in case of nuclear reaction small change in mass take place.

7 0
3 years ago
Read 2 more answers
Electrolysis is an endothermic process when an electric current is passed through water and separates it into hydrogen and oxyge
azamat

Answer:

IM SORRY I NEED THIS ONE

Explanation:

pls dont report

3 0
3 years ago
The change in internal energy for the combustion of 1.0 mol of octane at a pressure of 1.0 atm is -5084.1 kj . f the change in e
TEA [102]

<u>Given:</u>

Change in internal energy = ΔU = -5084.1 kJ

Change in enthalpy = ΔH = -5074.3 kJ

<u>To determine:</u>

The work done, W

<u>Explanation:</u>

Based on the first law of thermodynamics,

ΔH = ΔU + PΔV

the work done by a gas is given as:

W = -PΔV

Therefore:

ΔH = ΔU - W

W = ΔU-ΔH = -5084.1 -(-5074.3) = -9.8 kJ

Ans: Work done is -9.8 kJ


6 0
3 years ago
In a pedigree, when a circle of square is halfway shaded, is it
exis [7]
Ummm I think it is C. ( not sure)
6 0
3 years ago
Select the correct answer.
givi [52]

Answer:

{1s^2 2s^2 2p^6} 3s^2 3p^4

{Ne}3s^2 3p^4

Explanation:

i didnt understand the rest of that but this is the e- configuration on top and the bottom is noble gas configuration

6 0
3 years ago
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