How long does it for a car to cover 100 miles at 60 mi/hr? Use one of the following equations:
2 answers:
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Answer:
Magnetic field,
Explanation:
It is given that,
Number of turns, N = 320
Radius of the coil, r = 6 cm = 0.06 m
The distance from the center of one coil to the electron beam is 3 cm, x = 3 cm = 0.03 m
Current flowing through the coils, I = 0.5 A
We need to find the magnitude of the magnetic field at a location on the axis of the coils, midway between the coils. The magnetic field midway between the coils is given by :
B = 0.00239 T
or
So, the magnitude of the magnetic field at a location on the axis of the coils, midway between the coils is . Hence, this is the required solution.
kinetic energy is given by 1 /2
then you have to replace the figures
Answer
given,
Time period= T = 1.5 s
If it's moving through equilibrium point at t₀= 0 with v = 1.0 m/s
v_max=1.00 m/s
we know,
v_ max=A ω
v = A sin (ωt)
-0.50= -1.00 sin (ωt)
sin (ωt) = 0.5
t = 0.125 s
we have time period T=1.5 it is the time to complete one oscillation
means from eq to right,then left,then eq,then left,then from right to eq
time taken for left = t/4 = 0.125/4 = 0.375 s
smallest value of time
=0.375 + 0.125
= 0.50 sec
Set deer A's position to be the origin. Let be the distance from deer A to deer C. We're given that deer B is 95 m away from deer C, which means the length of the vector
is 95 (or
). Then
