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sertanlavr [38]
3 years ago
9

3. If the radius of Earth decreased, with no change in mass, your weight would

Physics
1 answer:
m_a_m_a [10]3 years ago
6 0

Answer:

The weight of the person would increase

Explanation:

The Universal Law of Gravitation gives the magnitude of the force between the masses of two objects (m1 and m2) separated a given distance "d" as:

F_g=G\,\frac{m_1*m_2}{d^2}

where G is the universal gravitational constant.

Our weight on Earth is this force between the Earth (of mass M) and ourselves (our mass m) at a distance that is the Earth's radius R:

Weight=G\frac{M*m}{R^2}

Now, if we keep all the values equal (mass of the Earth M and our mass m) except for the distance between the center of the Earth and our center of gravity (the radius of the Earth), we are going to have now a smaller radius (r) in the formula above:

Weight=G\frac{M*m}{r^2}

and dividing by a smaller number (r is smaller than R), will render a larger quotient. This means that the actual force (weight) will become larger, so the weight would clearly increase.

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oksian1 [2.3K]

Answer:

required distance is 233.35 m

Explanation:

Given the data in the question;

Sound intensity I = 1.62 × 10⁻⁶ W/m²

distance r = 165 m

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we know that;

Sound intensity I is proportional to 1/(distance)²

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Now, let r² be the distance where sound intensity is half, i.e I₂ = I₁/2

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Therefore, required distance is 233.35 m

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(wish i could help but im just answering for points)

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