1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sertanlavr [38]
2 years ago
9

3. If the radius of Earth decreased, with no change in mass, your weight would

Physics
1 answer:
m_a_m_a [10]2 years ago
6 0

Answer:

The weight of the person would increase

Explanation:

The Universal Law of Gravitation gives the magnitude of the force between the masses of two objects (m1 and m2) separated a given distance "d" as:

F_g=G\,\frac{m_1*m_2}{d^2}

where G is the universal gravitational constant.

Our weight on Earth is this force between the Earth (of mass M) and ourselves (our mass m) at a distance that is the Earth's radius R:

Weight=G\frac{M*m}{R^2}

Now, if we keep all the values equal (mass of the Earth M and our mass m) except for the distance between the center of the Earth and our center of gravity (the radius of the Earth), we are going to have now a smaller radius (r) in the formula above:

Weight=G\frac{M*m}{r^2}

and dividing by a smaller number (r is smaller than R), will render a larger quotient. This means that the actual force (weight) will become larger, so the weight would clearly increase.

You might be interested in
Newtons laws of motion
Viktor [21]

Answer:

Law 1. A body continues in its state of rest, or in uniform motion in a straight line, unless acted upon by a force.

Law 2. A body acted upon by a force moves in such a manner that the time rate of change of momentum equals the force.

Law 3. If two bodies exert forces on each other, these forces are equal in magnitude and opposite in direction.

7 0
2 years ago
-2 5/8 is bigger than -5/12
Neko [114]

Answer:

hey...................................

8 0
3 years ago
A 3.00-kg object has a velocity 1 6.00 i ^ 2 2.00 j ^2 m/s. (a) what is its kinetic energy at this moment? (b) what is the net w
tatyana61 [14]
(a) The velocity of the object on the x-axis is 6 m/s, while on the y-axis is 2 m/s, so the magnitude of its velocity is the resultant of the velocities on the two axes:
v= \sqrt{(6.00m/s)^2+(2.00 m/s)^2}=6.32 m/s
And so, the kinetic energy of the object is
K= \frac{1}{2}mv^2= \frac{1}{2}(3.00 kg)(6.32 m/s)^2=60 J

(b) The new velocity is 8.00 m/s on the x-axis and 4.00 m/s on the y-axis, so the magnitude of the new velocity is
v= \sqrt{(8.00 m/s)^2+(4.00 m/s)^2}=8.94 m/s
And so the new kinetic energy is
K= \frac{1}{2}mv^2= \frac{1}{2}(3.00 kg)(8.94 m/s)^2=120 J

So, the work done on the object is the variation of kinetic energy of the object:
W=\Delta K=120 J-60 J=60 J
7 0
2 years ago
What is the difference between Weight and Mass?<br>Please give a fair amount of detail!
Sidana [21]
The <em>mass</em> of an object is a measure of how much stuff it's made of.  So it's
a property of the object, like the object's length or color.  It doesn't depend on
where the object is located right now, or on what else is around it..

The <em>weight</em> of an object is the measure of the gravitational force between it
and something else.  The strength of the force depends on the size of both
masses, and also on how far apart they are.  So the weight does depend on
where the object is located right now, and on what else is around it.

I think that sums it up fairly well.
3 0
2 years ago
Read 2 more answers
A 1232 kg car moving north at 25.6 m/s collides with a 2028 kg car moving north at 17.5 m/s . They stick together. In what direc
Citrus2011 [14]

Answer:

I. Angle = 41.7° Northeast.

II. Vr = 7.08m/s

Explanation:

Let the two cars be denoted by A and B

<u>Given the following data;</u>

Mass of car A = 1232 Kg

Velocity of car A = 25.6 m/s

Mass of car B = 2028 Kg

Velocity of car B = 17.5m/s

First of all, we would solve for momentum;

Momentum = mass × velocity

Momentum, M1 = 1232 × 25.6

Momentum, M1 = 31539.2 Kgm/s

Momentum, M2 = 2028 × 17.5

Momentum, M2 = 35490 Kgm/s

Now, let's find the resultant momentum using the Pythagoras theorem;

R² = M1² + M2²

R² = 31539.2² + 35490²

R² = 994721136.6 + 1259540100

R² = 2254261237

Taking the square root of both sides, we have

Resultant momentum, R = 47479.06 Kgm/s

To find the direction;

Angle = tan¯¹(M1/M2)

Angle = tan¯¹(31539.2/35490)

Angle = tan¯¹(0.89)

<em>Angle = 41.7° Northeast.</em>

To find the speed;

R = (M1 + M2)Vr

47479.06 = (31539.2 + 35490)Vr

47479.06 = 67029.2Vr

Vr = 47479.06/67029.2

<em>Vr = 7.08m/s</em>

6 0
2 years ago
Other questions:
  • Calculate the acceleration if you push with a 20-N horizontal force against a 2-kg block on a horizontal friction- free air tabl
    5·1 answer
  • Suppose you walk 12.5 m in a direction exactly 19° south of west then you walk 19.5 m in a direction exactly 39° west of north.
    9·1 answer
  • Describe the proton gradient generated by the electron transport chain
    15·1 answer
  • The stored energy an object has due to its position is potential energy. True or False?
    10·2 answers
  • An avant-garde composer wants to use the Doppler effect in his new opera. As the soprano sings, he wants a large bat to fly towa
    14·1 answer
  • What value do we use to describe acceleration due to gravity
    14·1 answer
  • A proton is ejected from the sun at a speed of 2 x 10^6 m/s. How long does it take for this proton to reach earth? Answer in hou
    13·1 answer
  • You find it hard to ride faster on your bike because a force is pushing back on you. What type of force is slowing you down?
    15·2 answers
  • How do objects at rest and in motion respond in the presence of an external, unbalanced force?
    13·1 answer
  • If a system's internal energy increases by 250 kJ after the addition of375 kJ of energy as heat, what was the value ofthe work i
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!