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3 years ago

Define longitudinal wave

Physics

1 answer:

Alja [10]3 years ago

6 0

longitudinal wave, wave consisting of a periodic disturbance or vibration that takes place in the same direction as the advance of the wave. ... Sound moving through air also compresses and rarefies the gas in the direction of travel of the sound wave as they vibrate back and forth.

<u>FORMULA</u>

y = displacement of the point on the traveling sound wave

x = distance the point has traveled from the wave's source

y_0 = amplitude of the oscillations

\omega = angular frequency of the wave

t = time elapsed

c = speed of the wave

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Acceleration will only speed up an object true or false

EleoNora [17]

Yes
Acceleration, in physics, is the rate of change of velocity of an object.

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3 years ago

You are a meteorologist. While taking present weather observations, you note that the sky is full of wispy cirrus clouds estimat

Goshia [24]

Answer:

It will take 60 hours to pass your area

Explanation:

From the question we are told that

The the distance of wispy cirrus clouds is $d_w =6km = 6*10^3 m$

The slope is given as $S = 1:300 = \frac{1}{300}$

The speed is $v = 40km/hour$

Since the slope is 1:300 which indicates the change in the distance of the wispy cirrus clouds overhead to the distance of the warm front

Now if

1 km → 300 km

Then

$8km$ → x km

Cross multiplying and making x the subject

$x = 8 *300 = 2400 \ km$

Velocity is mathematically denoted as

$velocity(v) = \frac{Distance(d) }{Time(t) }$

Now making time the subject

$Time (t) = \frac{Distance }{Velocity}$

Now substituting values we have

$t =\frac{2400}{40}$

$= 60\ hours$

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3 years ago

What does democratized knowledge mean?

lutik1710 [3]

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3 years ago

Read 2 more answers

Magnitude of force F experienced by a certain object moving with speed v is given by F=Kv race to 2, where K is constant. Find t

My name is Ann [436]

<h2>Answer:</h2>

MT⁻¹

<h2>Explanation:</h2>

Given equation:

F = Kv --------------(i)

Where;

F = Magnitude of force experienced by the object

v = speed at which the object is moving

K = constant.

To get the dimension of K, follow the following steps:

i. <em>Make K subject of the formula in equation(i)</em>

K = F / v

ii.<em> Get the dimension of force F and speed v</em>

Dimension of force = MLT⁻²

Dimension of velocity = LT⁻¹

iii.<em> Substitute these dimensions into the result of (i) above;</em>

K = MLT⁻² / LT⁻¹

iv. <em>Simplify the result in (iii)</em>

<em>First, the </em><em>L</em><em>s in the numerator and denominator will cancel out</em>

K = MT⁻² / T⁻¹

<em>Next, the </em><em>T</em><em>s will be expressed as follows</em>

K = MT⁻² x T¹ [using the law of indices]

K = MT⁻²⁺¹

K = MT⁻¹

Therefore, the dimension of K is MT⁻¹

6 0

3 years ago

A 77.3 g mass is attached to a horizontal spring with a spring constant of 12.5 N/m and released from rest with an amplitude of

DENIUS [597]

Answer:

speed of the mass is 3.546106 m / s

Explanation:

given data

mass = 77.3 g = 77.3 × $10^{-3}$ kg

spring constant k = 12.5 N/m

amplitude A = 38.9 cm = 38.9 × $10^{-2}$ m

to find out

the speed of the mass

solution

we will apply here conservation energy that is

K.E + P.E = Total energy ..................1

so that Total energy = K.E max = P.E max

we know amplitude so we find out first P.E max that is

PE max = K.E + P.E

(1/2)kA² = (1/2)mv² + (1/2)kx²

kA^² = mv²+ kx²

so here v² will be

v² = k(A² - x²) / m

v = √[(k/m)×(A² - x²)] ............2

here x = (1/2)A so from from 2 equation

v = √[(k/m)×(A² - (A/2)²)]

v = √[(k/m)×(3/4×A²)]

now put all value

v = √[(12.5/ 77.3 × $10^{-3}$ )×(3/4×(38.9 × $10^{-2}$ )²)]

v = 3.546106 m / s

speed of the mass is 3.546106 m / s

6 0

3 years ago

Define longitudinal wave​

Define longitudinal wave