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earnstyle [38]
2 years ago
5

Define longitudinal wave​

Physics
1 answer:
Alja [10]2 years ago
6 0

longitudinal wave, wave consisting of a periodic disturbance or vibration that takes place in the same direction as the advance of the wave. ... Sound moving through air also compresses and rarefies the gas in the direction of travel of the sound wave as they vibrate back and forth.

<u>FORMULA</u>

<h2>y(x,t) = y0 \: cos \: (w(t -  \frac{x}{c} ))</h2>

y = displacement of the point on the traveling sound wave

x = distance the point has traveled from the wave's source

y_0 = amplitude of the oscillations

\omega = angular frequency of the wave

t = time elapsed

c = speed of the wave

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Because atoms of elements in the same group of the periodic table have the same number of neutrons, they have similar properties
AURORKA [14]
False. What actually determines the properties of elements are the electrons, or aka valence electrons. They are used to bond, which determines its properties. 
4 0
3 years ago
Which of these is an example of acceleration ?
anygoal [31]

Answer:

no picture or anything so cant anwser

Explanation:

8 0
3 years ago
Read 2 more answers
2. A 2000 kg car with speed 12.0 m/s hits a tree. The tree does not move or
krek1111 [17]

a) The work done by the tree is -1.44\cdot 10^5 J

b) The amount of force applied is 2880 N

Explanation:

a)

According to the work-energy theorem, the work done on the car is equal to the change in kinetic energy of the car. Therefore, we can write:

W=K_f - K_i = \frac{1}{2}mv^2 - \frac{1}{2}mu^2

where

W is the work done on the car

m is the mass of the car

u is its initial speed

v is its final speed

For the car in this problem, we have:

m = 2000 kg

u = 12.0 m/s

v = 0 (since the car comes to a stop, after the crash)

Therefore, the work done by the tree on the car is:

W=0-\frac{1}{2}(2000)(12.0)^2=-1.44\cdot 10^5 J

The work is negative because it is done in the direction opposite to the direction of motion of the car.

b)

The work done by the tree on the car can also be rewritten as

W=Fd

where

F is the force applied on the car

d is the displacement of the car during the collision

In this situation, we have:

W=-1.44\cdot 10^5 J is the work done

d=50.0 cm = 0.50 m is the displacement of the car during the collision

Solving the equation for F, we find the force exerted by the tree on the car:

F=\frac{W}{d}=\frac{-1.44\cdot 10^5 J}{0.50}=-2880 N

Where the negative sign means the force is applied opposite to the direction of motion of the car. Therefore, the magnitude of the force applied is 2880 N.

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

3 0
3 years ago
A dog walks 12 meters to the east and then 16 meters back to the west for this motion what is the distance moved What is the mag
FinnZ [79.3K]

The distance is 28 meters, and the displacement is -4.

For the distance it would be 12 + 16 = 28.

For the displacement it would be 12 - 16 = -4.

would really appreciate a brainliest! Hope this helped!

6 0
3 years ago
a radio antenna broadcasts a 1.0 MHz radio wav e with 21 kW of power. Assume that the radiation is emitted uniformly in all dire
My name is Ann [436]

Answer:

I=2.67\times 10^{-6}\ W/m

Explanation:

Given that,

Frequency of a radio antenna is 1 MHz

Power, P = 21 kW

We need to find the the waves intensity 25 km from the antenna . The object emits intenisty evenly in all direction. It can be given by :

I=\dfrac{P}{4\pi r^2}\\\\I=\dfrac{21\times 10^3}{4\pi (25000)^2}\\\\I=2.67\times 10^{-6}\ W/m

So, the wave intensity 25 km from the antenna is 2.67\times 10^{-6}\ W/m.

5 0
3 years ago
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