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OLEGan [10]
3 years ago
7

This reaction shows the complete combustion of octane, C8H18, a component of gasoline. How many moles of O2 are needed to burn 2

.40 mol of C8H18?
Chemistry
1 answer:
ANTONII [103]3 years ago
6 0
How you're going to answer this question is by doing a mole t - chart first you're going to put 2.40 mol of C8H18 opposite of the mol then you're going to find o2 which 256 on the bottom then multiply across to get the answer.

Hope this help, message me if you need more help 
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Do Alkali Metal Compounds form precipitates? And Why?
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3 years ago
Sulfur dioxide gas (SO2) and oxygen gas (O2) react to form the liquid product of sulfur trioxide (SO3). How much sulfur dioxide
taurus [48]
1) Balanced chemical equation:

2SO2 (g) +  O2 (g) -> 2SO3 (l)

2) Molar ratios

2 mol SO2 : 1 mol O2 : 2 mol SO3

3) Convert 6.00 g O2 to moles

number of moles = mass in grams / molar mass

number of moles = 6.00 g / 32 g/mol = 0.1875 mol O2.

4) Use proportions with the molar ratios

=> 2 moles SO2 / 1 mol O2 = x / 0.1875 mol O2

=> x = 0.1875 mol O2 * 2 mol SO2 / 1 mol O2 = 0.375 mol SO2.

5) Convert 0.375 mol SO2 to grams

mass in grams = number of moles * molar mass

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=> mass SO2 = 0.375 mol * 64 g / mol = 24.0 g

Answer: 24.0 g of SO2 are needed to react completely with 6.00 g O2.
7 0
3 years ago
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