Equilibrium will shift towards the products when temperature is decreased in an exothermic reaction of the formation of ammonia.
<h3>What is an exothermic reaction?</h3>
An exothermic reaction is a reaction in which heat content of the reactants is greater than the heat content of product.
In an exothermic reaction, heat is given off.
For an exothermic reaction in equilibrium, increasing temperature shifts equilibrium to the towards the left, towards the reactants.
On the other, equilibrium will shift towards the products when temperature is decreased.
Therefore, equilibrium will shift towards the products when temperature is decreased in the reaction of the formation of ammonia.
Learn more about exothermic reactions at: brainly.com/question/13892884
#SPJ1
Answer:
A
Explanation:
Ball bounces because of the difference in the air pressure on the outside of the ball, and opposite the point of impact, and the pressure inside of the ball. This means that the inside of the ball now has less space to contain the air molecules contained inside the ball, increasing the pressure inside the ball.
Explanation:
In the molecular equation for a reaction, all of the reactants and products are represented as neutral molecules (even soluble ionic compounds and strong acids). In the complete ionic equation, soluble ionic compounds and strong acids are rewritten as dissociated ions.
The net ionic equation is a chemical equation for a reaction that lists only those species participating in the reaction. The net ionic equation is commonly used in acid-base neutralization reactions, double displacement reactions, and redox reactions.
Answer : The oxidizing element is N and reducing element is O.
is act as an oxidizing agent as well as reducing agent.
Explanation :
An Oxidizing agent is the agent which has ability to oxidize other or a higher in oxidation number.
Reducing agent is the agent which has ability to reduce other or lower in oxidation number.
The given reaction is :
act as an oxidizing agent.
The oxidation number of N in is calculated as:
(+1)+(x)+3(-2) = 0
x = +5
And the oxidation number of N in 
is calculated as:
(+1)+(x)+2(-2) = 0
x = +3
From the oxidation number method, we conclude that the oxidation number reduced this means itself get reduced to and it can act as an oxidizing agent.
act as a reducing agent.
The oxidation number of O in is calculated as:
(+1)+(+5)+3(x) = 0
x = -2
The oxidation number of O in 
is Zero (o).
Now, we conclude that the oxidation number increases this means itself get oxidized to and it can act as reducing agent.
Like A B C D or like a mailed letter
