Answer:
[/tex] 408.8[/tex]
Explanation:
= thickness of the floor = 0.159 m
= thermal conductivity of wooden floor = 0.141 Wm⁻¹ ⁰C⁻¹
= Temperature of the interior of the cabin = 18.0 ⁰C
= Temperature of the air below the cabin = - 16.4 ⁰C
Difference in temperature is given as
= Difference in temperature =
⁰C
= Area of the floor = 13.4 m²
= Rate of heat conduction
Rate of heat conduction is given as
![Q = \frac{kA \Delta T}{t}](https://tex.z-dn.net/?f=Q%20%3D%20%5Cfrac%7BkA%20%5CDelta%20T%7D%7Bt%7D)
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Answer:
This was my best estimation of the answers
Answer:
<h2>
The force is ![36*10^-^9 N](https://tex.z-dn.net/?f=36%2A10%5E-%5E9%20N)
</h2>
Explanation:
According to newtons law on gravitation formula, which we are going to apply,
![F= \frac{Gm1m2}{d^2}](https://tex.z-dn.net/?f=F%3D%20%5Cfrac%7BGm1m2%7D%7Bd%5E2%7D)
Where G represents universal gravitation constant, ![6.67*10^-^1^1 N.m^2/kg^2](https://tex.z-dn.net/?f=6.67%2A10%5E-%5E1%5E1%20N.m%5E2%2Fkg%5E2)
Given data
m1= 90 kg
m2= 60 kg
d= 1 m
Substituting our given data into the formula we have
![F= \frac{6.67*10^-^1^1*90*60}{1^2}](https://tex.z-dn.net/?f=F%3D%20%5Cfrac%7B6.67%2A10%5E-%5E1%5E1%2A90%2A60%7D%7B1%5E2%7D)
![F= \frac{6.67*10^-^1^1*5.4*10^3}{1^2}\\\\F= 36*10^-^9 N](https://tex.z-dn.net/?f=F%3D%20%5Cfrac%7B6.67%2A10%5E-%5E1%5E1%2A5.4%2A10%5E3%7D%7B1%5E2%7D%5C%5C%5C%5CF%3D%2036%2A10%5E-%5E9%20N)
The temperature of the gas is 41.3 °C.
Answer:
The temperature of the gas is 41.3 °C.
Explanation:
So on combining the Boyle's and Charles law, we get the ideal law of gas that is PV=nRT. Here P is the pressure, V is the volume, n is the number of moles, R is gas constant and T is the temperature. The SI unit of pressure is atm. So we need to convert 1 Pa to 1 atm, that is 1 Pa = 9.86923×
atm. Thus, 171000 Pa = 1.6876 atm.
We know that the gas constant R = 0.0821 atmLMol–¹K-¹. Then the volume of the gas is given as 50 L and moles are given as 3.27 moles.
Then substituting all the values in ideal gas equation ,we get
1.6876×50=3.27×0.0821×T
Temperature = ![\frac{84.38}{0.268467} =314.3 K](https://tex.z-dn.net/?f=%5Cfrac%7B84.38%7D%7B0.268467%7D%20%3D314.3%20K)
So the temperature is obtained to be 314.3 K. As 0°C = 273 K,
Then 314.3 K = 314.3-273 °C=41.3 °C.
Thus, the temperature is 41.3 °C.