<h2>
Answer:</h2>
400N/m
<h2>
Explanation:</h2>
When n identical springs of stiffness k, are attached in series, the reciprocal of their equivalent stiffness (1 / m) is given by the sum of the reciprocal of their individual stiffnesses. i.e
= ∑ⁿ₁ [] -----------------------(i)
That is;
= + + + . . . + -------------------(ii)
If they have the same value of stiffness say s, then equation (ii) becomes;
= n x -----------------(iii)
Where;
n = number of springs
From the question,
There are 3 identical springs, each with stiffness of 1200N/m and they are attached in series. This implies that;
n = 3
s = 1200N/m
Now, to calculate the effective stiffness,m, (i.e the stiffness of a longer spring formed from the series combination of these springs), we substitute these values into equation (iii) above as follows;
= 3 x
=
=
Cross multiply;
m = 400N/m
Therefore, the stiffness of the longer spring is 400N/m
Formula for acceleration= v2-v1/time
so 22-4/3 is 6m/s^2
You can increase the turns of the coil and flow. The strength can be varied.
Answer:
220 N
Explanation:
When a shopping cart rolls into a parked car on the street, it hits the car with a force of 220 newtons.
We need to find the force the shopping cart experiences from the car.
We know that, Newton's third law of motion states that for every action there is an equal and opposite reaction.
Hence, the shopping cart experiences a force of 220 N from the car.
Answer:
Personally I think, that the answer is B.
Explanation: