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Andreyy89
2 years ago
6

A ray of light travelled from water into the air an angle of incidence of 30°. Calculate;

Physics
1 answer:
Dima020 [189]2 years ago
3 0

Answer:

speed = distance/time

just find the speed if it

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A 25 kg mass is accelerated by a force at a rate of 5 m/s2. What is the magnitude of the force that accelerates the man?
svlad2 [7]
Force=mass*acceleration
F=ma
F=25*5
F=100 N
8 0
3 years ago
Please help on this one?
bezimeni [28]

Using the given equation you get:

E = 1.99x10^-25 / 9.0x10^-6

Divide 1.99 by 9.0: 1.99/9.0 = 0.22

For the scientific notation, when dividing subtract the two exponents:

25 -6 = 19

So you now have 0.22 x 10^-19

Now you need to change the 0.22 to be in scientific notation form:

2.2 x 10^-20

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3 years ago
Kinetic friction acts on a baseball player sliding into first base. Will the player's velocity change?
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What is kelvin scale?
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<span>a scale of temperature with absolute zero as zero, and the triple point of water as exactly 273.16 degrees.</span>
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Read 2 more answers
A boy throws a ball of mass 0.22 kg straight upward with an initial speed of 29 m/s. When the ball returns to the boy, its speed
maksim [4K]

Answer:

The work is -67.76 J

Explanation:

The law of conservation of energy is considered one of one of the fundamental laws of physics and states that the total energy of an isolated system remains constant. except when it is transformed into other types of energy.

This is summed up in the principle that energy can neither be created nor destroyed in the universe, only transformed into other forms of energy.

In this case you must calculate the loss of kinetic energy. This loss is actually the work done against the resistive force in the air. Friction is the only force other than gravity that acts on the ball.

So, the loss of kinetic energy is \frac{1}{2} *m*(vf^{2} -vi^{2} )

You know:

  • mass=m=0.22 kg
  • Initial velocity of the ball: vi= 29 \frac{m}{s}

Final velocity of the ball: vf= 15 \frac{m}{s}

Replacing:

\frac{1}{2} *0.22 kg*(15^{2} -29^{2} )= -67.76 J

Friction work is always negative because friction is always against displacement.

<u><em>The work is -67.76 J</em></u>

5 0
3 years ago
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