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3 years ago

Which candle burned the longest time why

Chemistry

2 answers:

Kamila [148]3 years ago

7 0

Answer:

The one that burned longer because it burned longer

Explanation:

Art [367]3 years ago

5 0

Poured beeswax candles will burn the longest
Why: slowest due to the hardness of the wax and the high temperature needed to melt the wax

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Exposure of silver Chloride to sunlight for a long<br>duration turns grey due to

Tema [17]

Answer:

Exposure of silver chloride to sunlight for a long duration turns grey due to photolytic decomposition i.e decomposition in the presence of sunlight.

Explanation:

When silver chloride, AgCl is exposed to sunlight for a long time, it will undergo decomposition as the sunlight provides sufficient energy needed to decomposed the salt, AgCl to metallic silver and chlorine gas. This can be seen in the equation below:

2AgCl —> 2Ag + Cl2

5 0

3 years ago

Anaerobic Cellular Respiration

Natasha2012 [34]

Answer:

I A hole

Explanation:

I must be in a museum, because you truly are a work of art

3 0

3 years ago

Complete the chart. (Remember to enter a "0" if necessary.)

antoniya [11.8K]

Just remember how many electrons can each sublevel hold.

S=2
P=6
D=10

Since we have 10 for atomic number, we can assume we have 10 electrons

1S2
2S2
2P6
The rest have zero because we already have 10 (2+2+6=10)

3 0

4 years ago

Read 2 more answers

52° 31' 12.0288"N and 13° 24' 17.8344" E.<br> What continent is it on?

olga55 [171]

Answer: Europe

Explanation: it’s in germany

7 0

3 years ago

Draw the alkene formed when 1-heptyne is treated with hbr in the presence of peroxide.

Nimfa-mama [501]

<h2>Heptene formed is -</h2><h2> $CH_3-CH_2-CH_2-CH_2-CH_2-CH=CHBr$ </h2>

Explanation:

The two possibilities when the peroxide is not present

$CH_{3}-CH_{2}-CH_{2}-CH_{2}-CH_{2}-C$ ≡ $CH +HBr$ → $CH_3-CH_2-CH_2-CH_2-CH_2-CBr=CH_{2}$

$CH_3-CH_2-CH_2-CH_2-CH_2-CBr=CH_2$ + HBr → $CH_3-CH_2-CH_2-CH_2-CH_2-CBr_2-CH_3$

In presence peroxide,

$CH_3-CH_2-CH_2-CH_2-CH_2-C$ ≡ $CH$ + HBr → $CH_3-CH_2-CH_2-CH_2-CH_2-CH=CHBr$

When peroxides are present in the reaction mixture, hydrogen bromide adds to the triple bond of heptane with regioselectivity.

This reaction is opposite to that of Markovnikov's rule which says that when asymmetrical alkene reacts with a protic acid HX, then the hydrogen of an acid is attached to the carbon with more in number of hydrogen substituents, and the halide (X) group is attached to the carbon with more in number of substituents of alkyl.
One mole of HBr adds to one mole of 1-heptane.
The structure of heptene formed is -

$CH_3-CH_2-CH_2-CH_2-CH_2-CH=CHBr$

5 0

3 years ago