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2 years ago

N2(g) + 3H2(g) ⟶ 2NH3(g)

Chemistry

2 answers:

kramer2 years ago

4 0

Answer:

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Explanation:

Andrews [41]2 years ago

3 0

Answer:

3.3 mol is the answer

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Chemical reaction when chromium metal is immersed in an aqueous solution of cobalt(II) chloride.

Marrrta [24]

$2Cr + 3CoCl_2$ → $2CrCl_3 + 3Co$

Explanation:

The products formed are chromic chloride and cobalt.

Chromium + Cobaltous Chloride = Chromic Chloride + Cobalt

Type of reaction is Single Displacement (Substitution) which is there is a displacement of one atom.

Reactants used in the reaction are -

Chromium $(Cr)$

Cobaltous Chloride $(CoCl_2)$

Products formed in the reaction are -

Chromic Chloride $(CrCl_3)$

Cobalt $(Co)$

Hence, the chemical reaction is as follows -

$Cr + CoCl_2$ → $CrCl_3 + Co$

For balancing the above chemical equation we need to add a coefficient of 2 in front of chromium and of 3 in front of cobalt(II)chloride on right-hand-side while of 2 in front of chromium chloride and of 3 in front of carbon monoxide on left-hand-side of the equation.

Hence, the balanced equation is -

$2Cr + 3CoCl_2$ → $2CrCl_3 + 3Co$

3 0

3 years ago

There are two binary compounds of mercury and oxygen. heating either of them results in the decomposition of the compound, with

grandymaker [24]

$\text{Hg} \text{O}$ and $\text{Hg}_{2} \text{O}$ .

Assuming complete decomposition of both samples,

$m(\text{Hg}) = m(\text{residure})$
$m(\text{O}) = m(\text{loss})$

First compound:

$m(\text{O}) = m(\text{loss}) = 0.6498 - 0.6018 = 0.048 \; g$
$m(\text{Hg}) = m(\text{residure}) = 0.6018 \; g$

$n = m/M$ ; $0.6498 \; g$ of the first compound would contain

$n(\text{O atoms}) = 0.048 \; g / 16 \; g \cdot mol^{-1}= 0.003 \; mol$
$n(\text{Hg atoms}) = 0.6018 \; g / 200.58 \; g \cdot mol^{-1}= 0.003 \; mol$

Oxygen and mercury atoms seemingly exist in the first compound at a $1:1$ ratio; thus the empirical formula for this compound would be $\text{Hg} \text{O}$ where the subscript "1" is omitted.

Similarly, for the second compound

$m(\text{O}) = m(\text{loss}) = 0.016 \; g$
$m(\text{Hg}) = m(\text{residure}) = 0.4172 - 0.016 = 0.4012 \; g$

$n = m/M$ ; $0.4172 \; g$ of the first compound would contain

$n(\text{O atoms}) = 0.016 \; g / 16 \; g \cdot mol^{-1}= 0.001 \; mol$
$n(\text{Hg atoms}) = 0.4012 \; g / 200.58 \; g \cdot mol^{-1}= 0.002 \; mol$

$n(\text{Hg}) : n(\text{O}) \approx 2:1$ and therefore the empirical formula

$\text{Hg}_{2} \text{O}$ .

8 0

3 years ago

2. As NH4OH is added to an HCl solution, the pH of the solution

chubhunter [2.5K]

Answer:

Explanation:

Nh4OH + HCL ---> NH4Cl + H3O

so ph decreases as H3O increases

and OH also decreases

5 0

3 years ago

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Which element is the least reactive? Neon, Chlorine, Gallium or Tin

Katen [24]

Noble gases are supposed to be the least reactive elements so I’m assuming Neon would be the most least reactive out of all of them.

7 0

2 years ago

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Consider a neutrally charged atom that has an atomic mass number of 80, which includes 35 neutrons. how many electrons does this

ivanzaharov [21]

Atomic mass number is the number of protons and neutrons. Subtract 80-35=45 is the number of protons. Because the atom is neutrally charged, the number of protons must equal the number of electrons, so there are 45 electrons.

5 0

3 years ago

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