Answer:
0.17547 m
Explanation:
m = Mass of block = 
v = Velocity of block = 10.8 m/s
k = Spring constant = 125 N/m
A = Amplitude
The kinetic energy of the system is conserved
The amplitude of the resulting simple harmonic motion is 0.17547 m
Answer:
fundamental frequency of pipe will be equal to 74 Hz
Explanation:
We have given for a particular organ pipe two adjacent frequency are 296 Hz and 370 Hz
Speed of the sound in air is 343 m/sec
We have to find the fundamental frequency for the pipe
Fundamental frequency will be equal to difference of the two adjacent frequency
So fundamental frequency = 370 - 296 = 74 Hz
So fundamental frequency of pipe will be equal to 74 Hz
Answer:
α = - 1.883 rev/min²
Explanation:
Given
ωin = 113 rev/min
ωfin = 0 rev/min
t = 1.0 h = 60 min
α = ?
we can use the following equation
ωfin = ωin + α*t ⇒ α = (ωfin - ωin) / t
⇒ α = (0 rev/min - 113 rev/min) / (60 min)
⇒ α = - 1.883 rev/min²
Answer:
impulse = 8820 kg·
or 8820 N·s
Explanation:
Impulse J is equal to the average force 
multiplied by the elapsed time Δt or in equation form, J = Δt
As long as your force of 450 N is constant then that value is your average force and your elapsed time is 19.4 seconds.
Multiply these values.
You will get an impulse of 8820 kg· or 8820 N·s.
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