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aksik [14]
3 years ago
14

What is this temperature in degree celsius of 77.2k

Chemistry
1 answer:
nalin [4]3 years ago
7 0
Degree celsius plus 273.15 equals degree kelvin so 77.2 minus 273.15 equals -195.95
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By using chromatography
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All the molecules of a substance possess the "average kinetic energy" value.
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Answer:

true

Explanation:

when molecules of a solid substance is vibrating so, it means they are possessing average kinetic energy. thus, we can conclude that the statement all the molecules of a substance posses the average kinetic energy value is true.

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What property of argon is uses in light bulbs?
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Read 2 more answers
A student is asked to standardize a solution of potassium hydroxide. He weighs out 1.08 g potassium hydrogen phthalate (KHC8H4O4
natka813 [3]

Answer:

A. 0.143 M

B. 0.0523 M

Explanation:

A.

Let's consider the neutralization reaction between potassium hydroxide and potassium hydrogen phthalate (KHP).

KOH + KHC₈H₄O₄ → H₂O + K₂C₈H₄O₄

The molar mass of KHP is 204.22 g/mol. The moles corresponding to 1.08 g are:

1.08 g × (1 mol/204.22 g) = 5.28 × 10⁻³ mol

The molar ratio of KOH to KHC₈H₄O₄ is 1:1. The reacting moles of KOH are 5.28 × 10⁻³ moles.

5.28 × 10⁻³ moles of KOH occupy a volume of 36.8 mL. The molarity of the KOH solution is:

M = 5.28 × 10⁻³ mol / 0.0368 L = 0.143 M

B.

Let's consider the neutralization of potassium hydroxide and perchloric acid.

KOH + HClO₄ → KClO₄ + H₂O

When the molar ratio of acid (A) to base (B) is 1:1, we can use the following expression.

M_{A} \times V_{A} = M_{B} \times V_{B}\\M_{A} = \frac{M_{B} \times V_{B}}{V_{A}} \\M_{A} = \frac{0.143 M \times 10.1mL}{27.6mL}\\M_{A} =0.0523 M

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3 years ago
7. A hypothesis needs to be written in a specific format.
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a . knowledge and existing theories .

b. falsifiable scope

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