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3 years ago

Cho 200 g dung dịch NaCl 0,5M tác dụng hết với 400 ml AgNO3. Sau phản ứng thu được kết tủa và dung dịch không màu

Chemistry

1 answer:

ivolga24 [154]3 years ago

4 0

Answer:

Explanation:

a. NaCl+ AgNO3-----> NaNO3+ AgCl

b. Số mol của NaCl= 0,2*0,5= 0,1 (mol)

------> Số mol của kết tủa AgCl tạo thành= 0,1 mol (dựa vào phương trình hóa học)

-----> Khối lượng của kết tủa AgCl tạo thành= 0,1*143,5=14,35(g)

c. Số mol của AgNO3= số mol của NaCl= 0,1 (mol)

------> Nồng độ mol của dd AgNO3 đã tham gia phản ứng= $\frac{0,1}{0,4}$ =0,25(M)

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2. Fe(s) + O2(g) → Fe3O4(s) a. When 13.54 g of O2 is mixed with 12.21 g of Fe, which is the limiting reactant? b. What mass in g

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The percent yield shows the extent to which the reactants are converetd into products . The limiting reactant is used up in the reaction.

<h3>What is a limiting reactant?</h3>

A limiting reactant is the reactant that is in the least amount in the system. Now;

Number of moles of Fe = 12.21 g/56 g/mol = 0.22 moles

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If 3 moles of Fe reacts with 2 mole of O2

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If 3 mole of Fe produces 1 mole of Fe3O4(s)

0.22 moles of O2 produces 0.22 moles * 1 mole/3 moles of Fe3O4(s) = 0.1073 moles

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Number of moles of excess reactant = 0.42 moles - 0.15 moles = 0.27 moles

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A client who weighs 70 kg is receiving a solution of 0.9% sodium chloride (normal saline) 500 ml with dopamine 800 mg at 5 ml/ho

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The mcg/kg/minute the client is receiving is 1.904 mcg/kg/min whose weight is 70 kg.

1 milligram (mg) = 1000 micrograms (mcg) or 0.001 grams (g) 1 g = 1000 mg 1 kilogram (kg) = 1000 g 1 kg = 2.2 pound (lb) 1 liter (L) = 1000 milliliters (mL)

The number of mcg/kg/minute = flow rate × concentration ÷ mass of client

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mass of dopamine = 800 mg and

volume = 500 ml

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So, substituting the variables into the equation, we have

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