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telo118 [61]
3 years ago
7

It's not A. Please help.

Physics
1 answer:
Nadusha1986 [10]3 years ago
6 0

Answer:

It represents double composition

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The solar constant is a. the same for a sphere or for a circle. b. only about a quarter of all energy emitted by the sun. c. a c
kvasek [131]

Answer:

b

Explanation:

5 0
3 years ago
At t = 0, one toy car is set rolling on a straight track with initial position 13.5 cm, initial velocity -4.2 cm/s, and constant
Blizzard [7]
(a) We must first look at the formulas of the velocities of each toy car. v1 =
-4.2 + 2.60t. v2 = 5.20. When the two cars have equal speed, then 
v1 = v2
-4.2 + 2.60t = 5.20
2.60t = 9.40
t = 3.62 s

(b) Their speed would then be 5.20 m/s. The toy car does not change speed since it doest not have any acceleration.
(c) The two cars will pass each other when their positions are equal.
x1 = 13.5 - 4.2t + 0.5*2.60t^2
x2 = 8.5 + 5.20t
x1 = x2
13.5 - 4.2t + 1.30t^2 = 8.5 + 5.20t
1.30t^2 - 9.40t + 5.0 = 0
t = 6.65s or t = 0.58 s

--------------------

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

3 0
3 years ago
A thin electrical heating element provides a uniform heat flux qo" to the outer surface of a duct through which air flows. The d
Ivanshal [37]

Answer:

a)q= 2800 W/m²

b)To=59.4°C

Explanation:

Given that

L = 10 mm

K= 20 W/m·K

T=30°C

h= 100 W/m²K

Ti=58°C

a)

Heat flux q

q= h ΔT

q= 100 x (58 - 30 )

q= 2800 W/m²

b)

As we know that heat transfer by Fourier law given as

Q= K A ΔT/L

Lets take outer temperature is To

So by  Fourier law

To= Ti + qL/K

Now by putting the values

To= Ti + qL/K

To= 58 + 2800 \times \dfrac{ 0.01}{20}

To=59.4°C

5 0
3 years ago
A vessel at rest at the origin of an xy coordinate system explodes into three pieces. Just after the explosion, one piece, of ma
Sergeu [11.5K]

Answer:

25

Explanation:

magnitude and (b) direction (as an angle relative to the x axis) of the velocity

5 0
3 years ago
Several different compounds can share the same empirical formula. The Molecular weight for three compounds with the empirical fo
Pie

Molecular formulas:

  1. CH₂O;
  2. C₂H₄O₂;
  3. C₆H₁₂O₆.
<h3>Explanation</h3>

The empirical formula of a compound tells only the ratio between atoms of each element. The empirical formula CH₂O indicates that in this compound,

  • for each C atom, there are
  • two H atoms, and
  • one O atom.

The molecular weight (molar mass) of the molecule depends on how many such sets of atoms in each molecule. The empirical formula doesn't tell anything about that number.

It's possible to <em>add</em> more of those sets of atoms to a molecular formula to increase its molar mass. For every extra set of those atoms added, the molar mass increase by the mass of that set of atoms. The mass of one mole of C atoms, two mole of H atoms, and one mole of O atoms is 12.0 + 2\times 1.0 + 16.0 = 30.0\;\text{g}.

  • CH₂O- 30.0 g/mol;
  • C₂H₄O₂- 30.0 + 30.0 = 2 × 30.0 = 60.0 g/mol;
  • C₃H₆O₃- 30.0 + 30.0 + 30.0 = 3 × 30.0 = 90.0 g/mol.

It takes one set of those atoms to achieve a molar mass of 30.0 g/mol. Hence the molecular formula CH₂O.

It takes two sets of those atoms to achieve a molar mass of 60.0 g/mol. Hence the molecular formula C₂H₄O₂.

It takes \dfrac{180.0}{30.0} = 6 sets of those atoms to achieve a molar mass of 180.0 g/mol. Hence the molecular formula C₆H₁₂O₆.

5 0
3 years ago
Read 2 more answers
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