1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
amid [387]
2 years ago
8

When calcium metal (Ca) reacts with oxygen gas (O2), it produces the ionic compound calcium oxide (CaO). Write the balanced equa

tion for this reaction. Then, explain if this process meets the requirements to be considered a redox reaction. (6 points)
Chemistry
1 answer:
malfutka [58]2 years ago
7 0

The balanced chemical equation for the reaction is

2Ca(s) + O₂(g) → 2CaO(s)

and

The process meets the requirements to be considered a redox reaction.

From the question,

We are to write a balanced chemical equation for the reaction between Calcium metal and oxygen gas

The balanced chemical equation for the reaction is

2Ca(s) + O₂(g) → 2CaO(s)

This is the balanced chemical equation for the reaction

To determine whether the reaction meets the requirements to be considered a redox reaction,

We will define the term <em>redox reaction</em>

<em></em>

A <em>redox reaction</em>, also called oxidation-reduction reaction, is any chemical reaction in which the oxidation number of a participating chemical species changes.

From the balanced equation above we can observe that the oxidation number of the participating species(Calcium and oxygen) changed.

The oxidation number of Calcium changed from 0 to +2

and

The oxidation number of Oxygen changed from 0 to -2

∴ The process meets the requirements to be considered a redox reaction.

Hence, the balanced chemical equation for the reaction is

2Ca(s) + O₂(g) → 2CaO(s)

and

The process meets the requirements to be considered a redox reaction.

Learn more here: brainly.com/question/17716543

You might be interested in
Describe the overall enthalpy of the chemical reactants compared to the enthalpy of the chemical products in the combustion of p
Veronika [31]

Answer:

A thermochemical equation for the combustion of propane (C3H8)(C3H8) is written as follows:

C3H8(l)+5O2(g)→3CO2(g)+4H2O(g);ΔH∘rxnC3H8(l)+5O2(g)→3CO2(g)+4H2O(g);ΔHrxn∘ = -2202.0 kJ/mol

The value given for ΔH∘rxnΔHrxn∘ means that:

a. the reaction of one mole of propane absorbs 2202 kJ of energy from the surroundings.

b. the reaction is endothermic.

c. the enthalpy of formation of propane is 2202 kJ/mol.

d. the reaction of one mole of propane releases 2202 kJ of energy to the surroundings.

e. None of these.

3 0
1 year ago
How many moles of propane<br> react when 294 g of CO2 form?<br><br> C3H8 +502 → 3CO₂ + 4H₂O
tatiyna

2.23 moles of propane react when 294 g of CO₂ is formed .

<h3>What is moles ?</h3>

Moles is a unit which is equal to the molar mass of an element.

A reaction is given

C₃H₈ +50₂ → 3CO₂ + 4H₂O

Grams of CO₂ formed = 294 gm

In moles = 294 /44 = 6.68 moles.

Let x be the moles of C₃H₈ is x

Mole ratio of CO₂ to C₃H₈ = 3 : 1

so

6.68 /x = 3/1

x = 6.68 /3 = 2.23 moles

Therefore 2.23 moles of propane react when 294 g of CO₂ is formed .

To know more about Moles

brainly.com/question/26416088

#SPJ1

7 0
2 years ago
If the air temperature is the same as the temperature of your skin (about 30◦C), your body cannot get rid of heat by transferrin
Elenna [48]

Answer:

Explanation:

a )

energy produced per second = 500 J

Heat produced = 500 x .8 = 400 J per second.

If m be the mass of water evaporated per unit hour

m x latent heat = 400 x 60 x 60

= m x 2.42 x 10⁶ = 1.44 x 10⁶

m = .595 kg per hour

b )

volume of water = 595 mL

bottles = 595 / 750

.8 or 4/5 of bottle. per hour.

8 0
3 years ago
Final volume of Argon gas:
DerKrebs [107]

Answer:

6.78 × 10⁻³ L

Explanation:

Step 1: Write the balanced equation

Mg₃N₂(s) + 3 H₂O(g) ⇒ 3 MgO(s) + 2 NH₃(g)

Step 2: Calculate the moles corresponding to 10.2 mL (0.0102 L) of H₂O(g)

At STP, 1 mole of H₂O(g) has a volume of 22.4 L.

0.0102 L × 1 mol/22.4 L = 4.55 × 10⁻⁴ mol

Step 3: Calculate the moles of NH₃(g) formed from 4.55 × 10⁻⁴ moles of H₂O(g)

The molar ratio of H₂O to NH₃ is 3:2. The moles of NH₃ produced are 2/3 × 4.55 × 10⁻⁴ mol = 3.03 × 10⁻⁴ mol.

Step 4: Calculate the volume corresponding to 3.03 × 10⁻⁴ moles of NH₃

At STP, 1 mole of NH₃(g) has a volume of 22.4 L.

3.03 × 10⁻⁴ mol × 22.4 L/mol = 6.78 × 10⁻³ L

3 0
3 years ago
Please Help me if you can!:) i appreciate anything.
enot [183]

Explanation:

1

Number of nucleon =

Molarmassofnucleon

Massofatom

=

1.6726×10

−24

g/nucleon

3.32×10

−23

g

=19.8=20(approximately)

It is given that element comprises of 2 atoms

Hence,number of nucleon = 2×20=40

2

You have 4.70 mol H2O

There are two H atoms in 1 molecule H2O.

Therefore, there must be 2*4.70 = 9.40 mols H in 4.70 mols H2O.

How many mols O in 4.70 mols H2O? That's 4.70 mols, of course.

Said another way, you have 2 mols H for every 1 mol H2O and 1 mol O for every 1 mol H2O.

So for 50 mols H2O you have 100 mols H and 50 mol O.

7 0
2 years ago
Other questions:
  • Do bases contain hydrogen ions (H+)
    11·1 answer
  • During an experiment, iron powder and sulfur powder were mixed thoroughly and placed on a filter paper. When a magnet was moved
    5·2 answers
  • Which groups of elements on the periodic table form metal ions that do not require roman numerals in their names?
    13·1 answer
  • How does the polarity of water give it this solvent property
    11·2 answers
  • Science problem please help
    8·2 answers
  • `One way to make ammonia is to synthesize it directly from elemental nitrogen and hydrogen (though this isn't that easy). The eq
    12·2 answers
  • How does weathering change rocks and minerals
    6·1 answer
  • What would happen to other populations if they didn't have limitng factors?
    13·1 answer
  • Explain why vanadium (radius=134 pm) and copper (radius=128 pm) have nearly identical atomic radii, even though the atomic numbe
    12·1 answer
  • How does sodium become a negative ion of neon
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!