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Jobisdone [24]
2 years ago
8

A motor car is travelling at 144km/h in a 90km/h speed zone .The driver suddenly sees speed camera 80m ahead before the camera c

an read the cars speed .
Calculate the deceleration required to comply with the speed limit before being caught by the camera
Engineering
1 answer:
Kruka [31]2 years ago
4 0

The deceleration required to comply with the speed limit before being caught by the camera is 6.094 meters per square second.

Let assume that the motor car <em>decelerates</em> at <em>constant</em> rate. Given the <em>initial</em> and <em>final</em> speeds (v_{o}, v), in meters per second, and <em>travelled</em> distance (s), in meters, the deceleration (a), in meters per square second, is determined by this formula:

a = \frac{v^{2}-v_{o}^{2}}{2\cdot s}

If we know that v_{o} = 25\,\frac{m}{s}, v = 40\,\frac{m}{s} and s = 80\,m, then the deceleration required to comply with the speed limit is:

a = \frac{\left(25\,\frac{m}{s} \right)^{2}-\left(40\,\frac{m}{s} \right)^{2}}{2\cdot (80\,m)}

a = -6.094\,\frac{m}{s^{2}}

The deceleration required to comply with the speed limit before being caught by the camera is 6.094 meters per square second.

We kindly invite to check this question on uniform accelerated motion: brainly.com/question/12920060

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Full Question

1. Correct the following code and

2. Convert the do while loop the following code to a while loop

declare integer product

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Answer:

1. Code Correction

The errors in the code segment are:

a. The use of do while on line 4

You either use do or while product < 100

b. The use of double "" as open and end quotes for the string literal on line 5

c. The use of "loop" statement on line 7

The correction of the code segment is as follows:

declare integer product

declare integer number

product = 0

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declare integer product

declare integer number

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Do

display "Type your number"

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