Question

The total pressure of gas collected over water is 740.0 mmHg and the temperature is 24.0°C What is the pressure of

Answer 1

The pressure of the hydrogen gas formed is given by its partial pressure at

the given temperature.

The pressure of the hydrogen gas formed is approximately 717.38 mmHg.

Reasons:

The pressure of the hydrogen gas formed is given by the difference

between the vapor pressure of the gas collected and the vapor pressure of

water.

The vapor pressure of water at 24.0 °C is given by the Clausius-Clapeyron

Equation as follows;

$ln \left(\dfrac{P_2}{P_1} \right) = \dfrac{\Delta H_{vap}}{R} \cdot \left(\dfrac{1}{T_1} - \dfrac{1}{T_2} \right)$

Where;

P₁ = The partial pressure at temperature, T₁

P₂ = The pressure at temperature, T₂

We get;

$ln \left(\dfrac{P_2}{23.8 \ mmHg} \right) = \dfrac{44,000 \ J/mol}{8.3145 \ J/(mol \cdot K)} \cdot \left(\dfrac{1}{298 \ K} - \dfrac{1}{297.15 \ K} \right)$

The pressure of water at 24.0 °C, P₂ ≈ 22.62 mmHg

The vapor pressure of water at 24.0°C is 22.62 mmHg

Therefore;

The pressure of the hydrogen gas formed ≈ 740.0 mmHg - 22.62 mmHg = 717.38 mmHg

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