Answer:
[OH⁻] = 0.002 M
Explanation:
<u>The definition of pOH</u> is similar to the definition of pH:
This means that with a <u>given pOH value</u>, the calculation of [OH⁻] is a matter of algebra:
To remove the logarithm we increase 10 by the power of the pOH:
=[OH⁻]
Atoms do not always contain the same number of electrons and protons, although this state is common. When an atom has an equal number of electrons and protons, it has an equal number of negative electric charges (the electrons) and positive electric charges (the protons). The total electric charge of the atom is therefore zero and the atom is said to be neutral. In contrast, when an atom loses or gains an electron (or the rarer case of losing or gaining a proton, which requires a nuclear reaction), the total charges add up to something other than zero.
Quantitative data is numerical.
Qualitative data is non-numerical.
Hope this helps.
have a great day.
Answer : The amount of energy released would be, ![39.24\times 10^8J](https://tex.z-dn.net/?f=39.24%5Ctimes%2010%5E8J)
Solution : Given,
Mass = ![4.36\times 10^{-5}g=4.36\times 10^{-8}Kg](https://tex.z-dn.net/?f=4.36%5Ctimes%2010%5E%7B-5%7Dg%3D4.36%5Ctimes%2010%5E%7B-8%7DKg)
conversion : (1 Kg = 1000 g)
Speed of light = ![3\times 10^8m/s](https://tex.z-dn.net/?f=3%5Ctimes%2010%5E8m%2Fs)
Formula used :
![E=m\times c^2](https://tex.z-dn.net/?f=E%3Dm%5Ctimes%20c%5E2)
where,
E = energy released
m = mass
c = speed of light
Now put all the given values in this formula, we get
![E=(4.36\times 10^{-8}Kg)\times (3\times 10^8m/s)^2=39.24\times 10^8J](https://tex.z-dn.net/?f=E%3D%284.36%5Ctimes%2010%5E%7B-8%7DKg%29%5Ctimes%20%283%5Ctimes%2010%5E8m%2Fs%29%5E2%3D39.24%5Ctimes%2010%5E8J)
Therefore, the amount of energy released would be, ![39.24\times 10^8J](https://tex.z-dn.net/?f=39.24%5Ctimes%2010%5E8J)