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LUCKY_DIMON [66]
2 years ago
6

PLEASE HELP

Chemistry
1 answer:
butalik [34]2 years ago
6 0
Hand JAJDJAJS is she land sold widow sisis. Sisis. E
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Find oxidation number for the aucl4 in haucl4 is it 1 or -1?
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H^{+I}Au^{+VII}Cl_{4}^{-I}
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3 years ago
If you made 6 moles of NO2 How many grams of N2 did you use N2+2O2> 2NO2​
denis23 [38]

Answer: 1:2

Explanation:

Believe me its correct.

7 0
3 years ago
The concentration of HCl can be determined by titration with a primary standard such as Na2CO3 (sodium carbonate). The titration
Masteriza [31]

Answer:

The concentration of HCl is 0.275 M

Explanation:

<u>Step 1:</u> Data given

Mass of Na2CO3 = 0.521 grams

Molar mass of Na2CO3 = 105.99 g/mol

Volume of HCl = 35.7 mL

<u>Step 2: </u>The balanced equation:

2HCl + Na2CO3 → 2NaCl + CO2 + H2O

CO3(2-) + 2H+ ---> H2O + CO2

<u>Step 3</u>: Calculate moles of Na2CO3

Moles Na2CO3 = mass Na2CO3 / Molar mass Na2CO3

Moles Na2CO3 = 0.521 grams / 105.99 g/mol

Moles Na2CO3 = 0.0049 moles

<u>Step 4:</u> Calculate moles of HCl

For 1 mol of Na2CO3 consumed, we need 2 moles of HCl

moles of HCL = 2 * 0.0049 = 0.0098 moles HCl

<u>Step 5:</u> Calculate molarity of HCl

Molarity = number of moles of HCl / Volume (liters)

Molarity = 0.0098 moles / 0.0357 L

Molarity = 0.275 M

The concentration of HCl is 0.275 M

4 0
3 years ago
Read 2 more answers
Suppose you are titrating a sulfuric acid solution of unknown concentration with a sodium hydroxide solution according to the eq
pogonyaev

Answer:

Explanation:

H ₂ S O ₄ + 2 N a O H ⟶ 2 H ₂ O + N a ₂ S O ₄

29.09 mL of 0.639 M N a O H is mixed with 213.8 mL of H ₂ S O ₄

Let the concentration of H ₂ S O ₄ be S₂ .

In terms of normal or equivalent solution is will be 2 N  solution

From the formula S₁ V₁ = S₂ V₂

= 29.09 x .639 = 213.8 x  S₂

S₂ = .087 N solution

In terms of molar solution it will be .087 / 2 M

= .0435 M

5 0
3 years ago
Help please hurry lots of points
andrey2020 [161]
I think ionic hope it helps
7 0
3 years ago
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