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aleksandrvk [35]
3 years ago
9

How can increase the rate of the preparation copper i iodide?​

Chemistry
1 answer:
BARSIC [14]3 years ago
5 0

Answer:

Preparation. Copper(I) iodide can be prepared by heating iodine and copper in concentrated hydriodic acid, HI. In the laboratory however, copper(I) iodide is prepared by simply mixing an aqueous solution of potassium iodide and a soluble copper(II) salt such copper sulfate.

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Find an element that has the same
navik [9.2K]

Answer:sodium

Explanation: because its not hard to look on the PERIODIC TABLE

4 0
3 years ago
Write the complete balanced equation for the reaction between iron (III) oxide (Fe2O3) and water (H2O). You do not need to make
Alina [70]
Fe2O3+3H2O->2Fe(OH)3
6 0
4 years ago
For most atoms, a stable configuration of electrons is attained when the atom __________. hints hint 1. (click to open) for most
sveticcg [70]

Correct answer: has a completely filled outermost shell

Atoms of the element with complete outermost shells are stable. So, in order to attain stability the atom either loses electrons or gains electrons to completely fill the outermost shell. The stable electronic configuration for the s and p-block elements is exhibited by the noble gases or the group 8 elements. All the unstable atoms try to attain the electronic configuration of the nearest noble gas with completely filled outermost shell.

5 0
3 years ago
Element X had a mass of 300g and a 1/2 life of 10 years. how many grams will remain after 40 years?
kiruha [24]
<h3>Answer:</h3>

18.75 grams

<h3>Explanation:</h3>
  • Half-life refers to the time taken by a radioactive material to decay by half of the original mass.
  • In this case, the half-life of element X is 10 years, which means it takes 10 years for a given mass of the element to decay by half of its original mass.
  • To calculate the amount that remained after decay we use;

Remaining mass = Original mass × (1/2)^n, where n is the number of half-lives

Number of half-lives = Time for the decay ÷ Half-life

                                 = 40 years ÷ 10 years

                                  = 4

Therefore;

Remaining mass = 300 g × (1/2)⁴

                            = 300 g × 1/16

                             = 18.75 g

Hence, a mass of 300 g of an element X decays to 18.75 g after 40 years.

3 0
4 years ago
I have a question can someone answer these questions for me please?
Kitty [74]
1. C
2. E
3. A
4. B
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I hope that helps <3
8 0
2 years ago
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