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aleksandrvk [35]
2 years ago
9

How can increase the rate of the preparation copper i iodide?​

Chemistry
1 answer:
BARSIC [14]2 years ago
5 0

Answer:

Preparation. Copper(I) iodide can be prepared by heating iodine and copper in concentrated hydriodic acid, HI. In the laboratory however, copper(I) iodide is prepared by simply mixing an aqueous solution of potassium iodide and a soluble copper(II) salt such copper sulfate.

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What is the most specific classification of Ca(NO3)2
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3 years ago
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Ionic equation for reaction of koh(aq) with cucl2(aq)
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Answer:

2 KOH(aq) + CuCl2(aq) = 2 KCl(s) + Cu(OH)2

Explanation:

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How isa molecule of mercury different from a molocue of water
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<h2>Answer:</h2>

The density of mercury molecule is higher than water.

<h3>Explanation:</h3>

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3 years ago
When a piece of sodium metal is kept in water in chemical equation​
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Explanation:

Sodium metal reacts rapidly with water to form a colourless basic solution of sodium hydroxide (NaOH) and hydrogen gas (H2). The reaction continues even when the solution becomes basic. The resulting solution is basic because of the dissolved hydroxide. 

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Calculate the molality of a solution formed by adding 6.30 g NH4CL to 15.7 g of water
babymother [125]

Answer:

Molality = 7.5 mol/kg

Explanation:

Given data:

Mass of NH₄Cl = 6.30 g

Mass of water = 15.7 g (15.7/1000 =0.016 kg)

Molality = ?

Solution:

Formula of molality:

Molality = Moles of solute / mass of solvent in gram

Now we will first calculate the number of moles of solute( NH₄Cl )

Number of moles = mass/ molar mass

Molar mass of  NH₄Cl = 53.491 g/mol

Number of moles = 6.30 g/  53.491 g/mol

Number of moles =  0.12 mol

Now we will calculate the molality.

Molality = Moles of solute / mass of solvent in gram

Molality =  0.12 mol / 0.016 kg

Molality = 7.5 m

or        (m=mol/kg)

Molality = 7.5 mol/kg

6 0
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