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3 years ago

What is the molarity of Na+ ions in a 0.02M sodium phosphate solution?

Chemistry

1 answer:

Katyanochek1 [597]3 years ago

7 0

Answer:

.06 M NA+

Explanation:

You go from (.02M Na3PO4 / 1) x (3 mole Na+ / 1 mole Na3PO4) = .06 M Na+

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After mitosis, you have 2 cells that are the same as the parent cell. Why is it that your first cell was not the same as your pa

ladessa [460]

Answer:

During MITOSIS, the parent, diploid (2n), cell is divided to create two identical, diploid (2n), daughter cells. ... After cytokinesis, the ploidy of the daughter cells remains the same because each daughter cell contains 4 chromatids, as the parent cell did.

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3 years ago

If the reaction 2HgO --> 2Hg + O2 is endothermic, which bonds are the strongest?

Alika [10]

Endothermic reaction means the reactant side takes heat from surrounding and get decomposed i.e ∆H=-ve
If the equation is exothermic then it means the reactant is happy to decompose .But it's not as it's endothermic

Now

HgO is Omitted from our solution option.

Hg is a atom so no bonds hence no bond strength occurs.

O_2 is a molecule and so it's our answer .

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2 years ago

Write a balanced equation for the complete oxidation reaction that occurs when ethane burns in air

damaskus [11]

<h3>Balanced equation : 2C₂H₆ (g) + 7O₂ (g) ⟶ 4CO₂ (g) + 6H₂O (ℓ)</h3><h3>Further explanation</h3>

Alkanes are saturated hydrocarbons that have single bonds in chains

General formula for alkanes :

$\tt \large{\bold{C_nH_{2n+2}}$

Hydrocarbon combustion reactions (specifically alkanes)

$\large {\box {\bold{C_nH _ (_2_n _ + _ 2_) + \dfrac {3n + 1} {2} O_2 \Rightarrow nCO_2 + (n + 1) H_2O}}}$

So that the burning of ethane with air (oxygen):

$\tt C_2H_6+\dfrac{7}{2}O_2\rightarrow 2CO_2+3H_2O$

2C₂H₆ (g) + 7O₂ (g) ⟶ 4CO₂ (g) + 6H₂O (ℓ)

or we can use mathematical equations to solve equilibrium chemical equations by giving the coefficients for each compound involved in the reaction

C₂H₆ (g) + aO₂ (g) ⟶ bCO₂ (g) + cH₂O (ℓ)

C : left 2, right b ⇒ b=2

H: left 6, right 2c⇒ 2c=6⇒ c= 3

O : left 2a, right 2b+c⇒ 2a=2b+c⇒2a=2.2+3⇒2a=7⇒a=7/2

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4 years ago

A gas expands from a volume of 2.00L at 36.0oC to a volume of 2.50 L, what is the final temperature, if the pressure is constant

lakkis [162]

We shall consider V, the volume and T, the temperature.
According to Boyle's Laws:
$\frac{V1}{T1} = \frac{V2}{T2}$
In our case:
$\frac{2.00}{36.0} = \frac{2.50}{T2} =\ \textgreater \ T2= \frac{2.50*36.00}{2.00} = 45$

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4 years ago

Read 2 more answers

Complete the transmutation equation below. Assume that there is only one unknown product. Np93239→Pu94239+?

aliya0001 [1]

I have attached the answer. hopefully, i read the problems correctly. let me know if I did not.

both problems are an example of beta decays. when an atoms' atomic number is increased by one. this is symbolized with -1 e

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3 years ago