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BARSIC [14]
3 years ago
11

1 year = 365 days

Chemistry
1 answer:
BARSIC [14]3 years ago
3 0
114.2 years

1,000,000/24= 41,666.66666666667

41,666.66666666667/365= 114.1552511415525

114.1552511415525 rounded to the nearest tenth is 114.2
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How many seconds would it take to deposit 17.3 g of ag (atomic mass = 107.87) from a solution of agno3 using a current of 10.00
Brums [2.3K]
Data Given:

Time = t = ?

Current = I = 10 A

Faradays Constant = F = 96500

Chemical equivalent = e = 107.86/1 = 107.86 g

Amount Deposited = W = 17.3 g

Solution:
             According to Faraday's Law,

                                          W  =  I t e / F

Solving for t,

                                          t  =  W F / I e
Putting values,
                                          t  =  (17.3 g × 96500) ÷ (10 A × 107.86 g)

                                          t  =  1547.79 s

                                          t  = 1.54 × 10³ s
5 0
3 years ago
At 500 K in the presence of a copper surface , ethanoldecomposes according to the equation
klio [65]

Answer:

Explanation:

rate of reaction

= -ve change in pressure of ethanol / time

= - (250 -237 )/100 = - 13 / 100 torr/s

= - 0.13 torr/s

next

- (237 - 224 )/100 = - 13 / 100 torr/s

= - .13 torr/s

next

- (224 - 211 )/100 = - 13 / 100 torr/s

= - .13 torr/s

so on

So rate of reaction is constant and it does not depend upon concentration or pressure of reactant .

So order of reaction is zero.

rate of reaction =K  [C₂H₅OH]⁰

K is rate constant

K = .13 torr/s

In 900 s decrease in pressure

= 900 x .13 = 117

So after 900s , pressure of ethanol will be

250 - 117 = 133 torr

8 0
3 years ago
A buret is filled with 0.1517 M naoh A 25.0 mL portion of an unknown acid and two drops of indicator are added to an Erlenmeyer
antiseptic1488 [7]

Answer:

molarity of acid =0.0132 M

Explanation:

We are considering that the unknown acid is monoprotic. Let the acid is HA.

The reaction between NaOH and acid will be:

NaOH+HA--->NaA+H_{2}O

Thus one mole of acid will react with one mole of base.

The moles of base reacted = molarity of NaOH X volume of NaOH

The volume of NaOH used = Final burette reading - Initial reading

Volume of NaOH used = 22.50-0.55= 21.95 mL

Moles of NaOH = 0.1517X21.95=3.33 mmole

The moles of acid reacted = 3.33 mmole

The molarity of acid will be = \frac{mmole}{volumne(mL)}=\frac{0.33}{25}=0.0132M

4 0
3 years ago
A student mixes some sugar into a cup of hot water. The sugar dissolves in the liquid. What are the BEST ways for the student to
polet [3.4K]
You would have to evaporate the water to get just the sugar

6 0
3 years ago
How do you unlock a post test on edmentum?
postnew [5]

Explanation:

A post-test or a mastery test can be unlocked if the learner who has the of it previously can complete the given tutorial with the test.

After the tutorial with the test, the learner will have to complete everything and if he passes the test with a completed answer then he will see that the Mastery Test has been unlocked. Also after the mastery test is unlocked it can be done again.

8 0
3 years ago
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