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Umnica [9.8K]
3 years ago
13

Dont need work pls help

Chemistry
1 answer:
Ulleksa [173]3 years ago
7 0
The answer is a low is the correct answer
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PLZ HELP ME WITH MY WORK​
Delvig [45]

Answer:

neutrons should be added with the protons

4 0
3 years ago
Which of the following is a mixture <br><br> Water<br><br> Ink<br><br> Alcohol <br><br> Mercury
Zepler [3.9K]
Paper chromatography can be applied to "ink" to determine if it is a pure substance or a "mixture" of pure substances (in which two or more pure substances are combined). Since, tested with paper chromatography, "ink" separates into its constituent pure substances, Ink is a mixture.

I hope this helps.

P.S. Thank you for choosing me as brainliest answer on my last.
4 0
4 years ago
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Suppose that a student doing this experiment ran into some procedural and calculation difficulties. State the effect each of the
Bingel [31]
The only one i can make sense out of would be: <span>
(1) "</span><span>After the reaction was completed, the student failed to withdraw the rod to its original position before taking the second buret reading." </span><em>this would affect the volume, since the rod is submerged in the solution, it would affect the reading (it would appear as a greater volume).</em>
5 0
3 years ago
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During titration, it is very common to have some NaOH spilled to the inside wall of Erlenmeyer flask. Ideally, these spilled NaO
GREYUIT [131]

Answer:

Its the first option

Explanation:

The volume of NaOH  added will be more than that which is needed to  neutralise the acetic acid. As the result is calculated from the volume of NAOH added from the burette, the result will be higher than the true result.

4 0
3 years ago
The ksp of copper(ii) carbonate, cuco3, is 1.4 × 10-10. calculate the solubility of this compound in g/l.
Mekhanik [1.2K]
To solve for the solubility of this compound:Cu ^ + 2 + CO3 ^ -2 = [x] [x] = x^2 1.4 x 10 ^ -10 = x^2 x = 1.1832 x 10 ^ -5 1.1832 x 10 ^ -5 moles/ L x 123.526 g/mol (molar mass) is equals to 1.5 x 10 ^-3 g/L is the solubility of this compound - CuCO3.
8 0
3 years ago
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