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timurjin [86]
3 years ago
9

Complete combustion of 6.4g of compound K produced 8.8 g of carbon dioxide and 7.2 g of water. Calculate the empirical formula o

f K. ​
Chemistry
1 answer:
Elenna [48]3 years ago
7 0
Lh (x1)78.009+1= 0.0000567
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Write a definition for each word and use each word in a sentence.<br> crystallization and organic
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Crystallization is the solidification of atoms or molecules into a highly structured form called a crystal.

Explanation:

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When combined in the correct ratio hydrogen and oxygen atoms can form water as shown below
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What takes longer to melt a small quantity or a large quantity?
My name is Ann [436]

Answer:

A large quantity

Explanation:

A large quantity will take much longer to melt compared to a small quantity of the same matter.

The rate of melt of a substance is particularly a function of the nature of the substance and the amount of energy supplied to it.

If we assume that we are dealing with different quantities of the same substance, then the one that has more mass will melt faster because less energy would be required to change its state.

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7 0
3 years ago
If 0.600mol of chloride gas reacted with 0.500mol of aluminium metal to produce aluminium chloride,which reactant is in excess?h
Rus_ich [418]

Answer:

The balanced chemical equation: 2 Al + 3Cl2→ 2 AlCl3

Mole-mole relationship: 2 moles Al + 3 moles Cl2→ 2 moles AlCl3

Given: 0.600 moleCl2; 0.500 mole Al

Required: Excess reactant___; Number of moles of AlCl3 produced__

Solution: Use dimensional analysis using the mole-mole rel

0.600 mole Cl2 * 2 moles Al/3 moles Cl2 = 0.4 mole Al

0.5 mole Al* 3 moles Cl2/2 moles Al = 0.75 mole Cl2

Based on the given:

0.6mole Cl2 + 0.4 mole Al ( this is possible based on the given)

0.5mole Al + 0.75 mole Cl2 (this is not possible because the given is only 0.600 mole of Cl 2)

Answer: Excess reactant is Al; Limiting reactant is Cl2

The amount of AlCl3 produced = 0.6 mole Cl2 + 0.4 mole Al = 1.0 mole AlCl3

4 0
3 years ago
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