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Effectus [21]
3 years ago
13

What is the acceleration of an elevator that weighs 5200 kg with a force of 35 N ?

Physics
1 answer:
borishaifa [10]3 years ago
7 0

Answer:

<h2>0.007 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{35}{5200}  = 0.006730 \\

We have the final answer as

<h3>0.007 m/s²</h3>

Hope this helps you

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lutik1710 [3]

Coulomb's Law

Given:

F = 3.0 x 10^-3 Newton

d = 6.0 x 10^2 meters

Q1 = 3.3x 10^-8 Coulombs

k = 9.0 x 10^9 Newton*m^2/Coulombs^2

Required:

Q2 =?

Formula:

F = k • Q1 • Q2 / d²

Solution:

So, to solve for Q2

 

Q2 = F • d²/ k • Q1

Q2 = (3.0 x 10^-3 Newton) • (6.0 x 10^2 m)² / (9.0 x 10^9 Newton*m²/Coulombs²) • (3.3x 10^-8 Coulombs)

Q2 = (3.0 x 10^-3 Newton) • (360 000 m²) / (297 Newton*m²/Coulombs)

Q2 = 1080 Newton*m²/ (297 Newton*m²/Coulombs)

Then, take the reciprocal of the denominator and start multiplying

Q2 = 1080 • 1 Coulombs/297

Q2 = 1080 Coulombs / 297

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Q2 = 3.64 Coulumbs

6 0
3 years ago
Read 2 more answers
Can you make the work output of a machine greater than the work input?
ExtremeBDS [4]

Answer:

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5 0
3 years ago
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erik [133]

Answer:

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Explanation:

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What electrical appliance was invented in 1910
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I think the toaster was invented in 1910

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