Answer:
B) 2g
Explanation:
<u>Given the following data;</u>
Velocity, v = 14m/s
Radius, r = 10m
To find the centripetal acceleration;
Substituting into the equation, we have;
Acceleration, a = 19.6m/s²
In terms of acceleration due to gravity, g = 9.8m/s²
We would divide by g;
Acceleration, a = 19.6/9.8 = 2
Hence, centripetal acceleration = 2g
Therefore, the rider's centripetal acceleration in terms of g, the acceleration due to gravity is 2g.
Answer:
ΔE = GMm/24R
Explanation:
centripetal acceleration a = V^2 / R = 2T/mr
T= kinetic energy
m= mass of satellite, r= radius of earth
= gravitational acceleration = GM / r^2
Now, solving for the kinetic energy:
T = GMm / 2r = -1/2 U,
where U is the potential energy
So the total energy is:
E = T+U = -GMm / 2r
Now we want to find the energy difference as r goes from one orbital radius to another:
ΔE = GMm/2 (1/R_1 - 1/R_2)
So in this case, R_1 is 3R (planet's radius + orbital altitude) and R_2 is 4R
ΔE = GMm/2R (1/3 - 1/4)
ΔE = GMm/24R
Answer:
Gravity force=mass x acceleration due to gravity
Explanation:
Gravity force=mass x acceleration due to gravity