Answer:
Part A: 2N₂O(g) ⇄ 2N₂(g) + O₂(g)
Part B: -r = K*[N₂O]²
Part C: K= k1*k2
Explanation:
Part A
To do the balance chemical question for the overall chemical reaction, we must sum the reaction of the steps, eliminating the intermediaries, which are the compounds that have the same amount both at reactants and products (bolded).
N₂O(g) ⇄ N₂(g) + O(g)
N₂O(g) + O(g) ⇄ N₂(g) + O₂(g)
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2N₂O(g) + O(g) ⇄ 2N₂(g) + O(g) + O₂(g)
2N₂O(g) ⇄ 2N₂(g) + O₂(g)
Part B
The velocity of the reaction (r) can be calculated based on the reactants or based on the products. Let's do it based on the disappearing of the reactant. Because it is disappearing, the variation at its concentration must be negative, so the rate will be negative.
Let's suppose its an elementary reaction, so, the concentration of the reactant must be elevated by its coefficient. And let's call the overall rate constant as K:
-r = K*[N₂O]²
Part C
Because the steps were summed, and the reactions were not multiplied by a constant or inverted, the constant K is just the multiplication of the constants of the steps:
K= k1*k2
The most abundant element in the Sun and in the stars are hydrogen and helium. Like most of the stars, there is a spontaneous radioactive reaction happening in the Sun. Hydrogen is transformed into Helium. As long as the stars are young, the most abundant element is hydrogen.
<u>Answer:</u> The number of moles of 
is 0.05 moles.
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
We are given:
Molarity of solution = 0.10 mol/L
Volume of solution = 1 L
Putting values in above equation, we get:
The chemical reaction for the ionization of sodium sulfate follows the equation:
By Stoichiometry of the reaction:
2 moles of sodium ions are produced by 1 mole of sodium sulfate
So, 0.10 moles of sodium ions will be produced by = 
of sodium sulfate.
Hence, the number of moles of is 0.05 moles.
Answer:
the answer is descriptive
Explanation:
descriotive never ever have hypothisis
