All categories

3 years ago

PLZ HURRY

Chemistry

1 answer:

zalisa [80]3 years ago

7 0

because sun dont orbits

You might be interested in

What is the relationship between producers and consumers in a food chain a producers eat consumers b consumers eat producers c p

allochka39001 [22]

Answer:

b consumers eat producers

Explanation:

In a food chain, the consumers are living organisms that eat organisms from a different population. Examples are herbivores like goats.

Producers make their own food in the food chain. Examples are plants.

The relationship between consumer and producers is hence that consumers consume / eat producers. Goats eat grass.

The correct option is;

b consumers eat producers

3 0

3 years ago

The picture below is a great example of __________ biodiversity.

ki77a [65]

Answer:

number three is the answer moderate

4 0

2 years ago

Read 2 more answers

Ayye yoo who want to answer this question ill give brainlist :)

frez [133]

Answer:

noble-gas notation

Explanation:

5 0

2 years ago

I NEED HELP PLEASE!!!! CHEMISTRY QUESTION: If 38 g of Li3P and 15 grams of Al2O3 are reacted, what total mass of products will r

maksim [4K]

Answer:

21.5 g.

Explanation:

Hello!

In this case, since the reaction between the given compounds is:

$2Li_3P+Al_2O_3\rightarrow 3Li_2O+2AlP$

We can see that according to the law of conservation of mass, which states that matter is neither created nor destroyed during a chemical reaction, the total mass of products equals the total mass of reactants based on the stoichiometric proportions; in such a way, we first need to compute the reacted moles of Li3P as shown below:

$n_{Li_3P}^{reacted}=38gLi_3P*\frac{1molLi_3P}{51.8gLi_3P}=0.73molLi_3P$

Now, the moles of Li3P consumed by 15 g of Al2O3:

$n_{Li_3P}^{consumed \ by \ Al_2O_3}=15gAl_2O_3*\frac{1molAl_2O_3}{101.96gAl_2O_3} *\frac{2molLi_3P}{1molAl_2O_3} =0.29molLi_3P$

Thus, we infer that just 0.29 moles of 0.73 react to form products; which means that the mass of formed products is:

$m_{Li_2O}=0.29molLi_3P*\frac{3molLi_2O}{2molLi_3P} *\frac{29.88gLi_2O}{1molLi_2O} =13gLi_2O\\\\m_{AlP}=0.29molLi_3P*\frac{2molAlP}{2molLi_3P} *\frac{57.95gAlP}{1molAlP} =8.5gAlP$

Therefore, the total mass of products is:

$m_{products}=13g+8.5g\\\\m_{products}=21.5g$

Which is not the same to the reactants (53 g) because there is an excess of Li₃P.

Best Regards!

7 0

3 years ago

Which one is NOT part of the cell theory?

worty [1.4K]

<u>Answer:</u>

All living things are not made of cells.

5 0

2 years ago