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Advocard [28]
3 years ago
15

Which unequal condition causes a sea breeze to develop?

Physics
1 answer:
pickupchik [31]3 years ago
8 0
Drier air Overland then water BR &/BR are the answers so the second one the second I’m in the first option
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Pls help i will be so happy thank you
Anvisha [2.4K]

Answer:

below given.

Explanation:

1) linear/direct

2) Indirect

3) linear/direct

4)  quadratic

5) Inverse

6) linear/direct

7) Inverse / Indirect

8) Inverse / Indirect

4 0
2 years ago
Which is not a form of light?
kifflom [539]

Radio waves, Middle-C, and halitosis are not forms of light.

8 0
3 years ago
The Doppler effect suggests that sound waves are relative to the observer. You know if an object is coming or going from the sou
mrs_skeptik [129]
A. Form the Brightness of the light
5 0
3 years ago
Read 2 more answers
Calculate the number of free electrons per cubic meter for some hypothetical metal, assuming that there are 1.3 free electrons p
boyakko [2]

Answer:

The number of free electrons per cubic meter is 7.61\times 10^{28}\ m^{-3}

Explanation:

It is given that,

The number of free electrons per cubic meter is, 1.3

Electrical conductivity of metal, \sigma=6.8\times 10^7\ \Omega^{-1}m^{-1}

Density of metal, \rho=10.5\ g/cm^3

Atomic weight, A = 107.87 g/mol

Let n is the number of  free electrons per cubic meter such that,

n=1.3\ N

n=1.3(\dfrac{\rho N_A}{A})

Where

\rho is the density of silver atom

N_A is the Avogadro number

A is the atomic weight of silver

n=1.3\times (\dfrac{10.5\ g/cm^3\times 6.02\times 10^{23}\ atoms/mol}{107.87\ g/mol})

n=7.61\times 10^{22}\ cm^{-3}

or

n=7.61\times 10^{28}\ m^{-3}

Hence, this is the required solution.

6 0
2 years ago
A object is located 16.0 cm in front of a converging lens whose focal length is 12.0 cm. A diverging lers ength of 10.0 cm is lo
Anuta_ua [19.1K]

Answer:

first lens v = 48 cm

second lens v = -15.6 cm

magnification =  1.67

final image is virtual

and final image is upright

Explanation:

given data

distance = 16 cm

focal length f1 = 12 cm

focal length f2 = 10.0 cm

to find out

location of the final image and magnification and Type of image

solution

we apply here lens formula that is

1/f = 1/v + 1/u     .....................1

put here all value and find v  for 1st lens

1/12 = 1/v + 1/16

v = 48 cm

and  find v  for 2nd lens

here u = 20- 48 = -28

- 1/10 = 1/v - 1/28

v = -15.6 cm

and

magnification = first lens (v/u) ×  second lens ( v/u)

magnification =  (-15.6/-28) ×  ( 48/16)

magnification =  1.67

so here final image is virtual

and final image is upright

6 0
3 years ago
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