Potassium sulfate has a solubility of 15g/100g water at 40 Celsius. A solution is prepared by adding 39.0g of potassium sulfate
1 answer:
Answer:
5.25 grams of potassium sulfate will get crystallize out.
Explanation:
Solubility of potassium sulfate at 40 °C = 15 g/100 g
This means that at 40 °C 15 g of potassium sulfate will get completely dissolved in 100 of water.
39.0 g of potassium sulfate to 225 g water, carefully heating the solution.
Amount of potassium sulphate will get dissolve in 225 g of water at 40 °C will be:
× 225 = 33.75g
Amount of potassium sulfate precipitated out by the solution:
= 39.0 g-33.75 g = 5.25 g
At 40 °C 5.25 g of potassium sulfate will get precipitate out from the solution which means that solution is saturated.
Saturated solution are solution in which solute is dissolved in maximum amount. Further addition of solute results in precipitation of solute form the solution.
5.25 grams of potassium sulfate will get crystallize out.
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Answer : The correct option is, (C) 2, 4 and 5.
Explanation :
Combustion reaction : It is a type of reaction in which a hydrocarbon react with an oxygen molecule to give carbon dioxide, water as a product.
For example : Methane react with oxygen to give carbon dioxide and water.
In the given list of chemical substances, are in oxide form. They can not be both reactant and product of a single combustion reaction.
In the given list, is the only hydrocarbon which shows a combustion reaction. That means
react with
to give
and
as a product.
The balanced combustion reaction of is,
Therefore, the correct answer is, (C) 2, 4, and 5.
Answer : The partial pressure of at equilibrium are, 1.133, 2.009, 0.574 bar respectively. The total pressure at equilibrium is, 3.716 bar
Solution : Given,
Initial pressure of = 1.42 bar
Initial pressure of = 2.87 bar
= 0.036
The given equilibrium reaction is,
Initially 1.42 2.87 0
At equilibrium (1.42-x) (2.87-3x) 2x
The expression of will be,
Now put all the values of partial pressure, we get
By solving the term x, we get
From the values of 'x' we conclude that, x = 3.889 can not more than initial partial pressures. So, the value of 'x' which is equal to 3.889 is not consider.
Thus, the partial pressure of at equilibrium = 2x = 2 × 0.287 = 0.574 bar
The partial pressure of at equilibrium = (1.42-x) = (1.42-0.287) = 1.133 bar
The partial pressure of at equilibrium = (2.87-3x) = [2.87-3(0.287)] = 2.009 bar
The total pressure at equilibrium = Partial pressure of + Partial pressure of
+ Partial pressure of
The total pressure at equilibrium = 1.133 + 2.009 + 0.574 = 3.716 bar
Answer: The density of the object will be
Explanation:
Density is defined as the mass contained per unit volume.
Given : Mass of object = 19.6 grams
Volume of object=
Putting in the values we get:
Thus density of the object will be