Answer:
The stress is
Explanation:
From the question we are told that
The diameter of the post is
The length is
The weight of the loading mass
Generally the radius of the post is mathematically represented as
=>
Generally the area of the post is
=>
=>
Generally the weight exerted by the load is mathematically represented as
=>
=>
Generally the stress is mathematically represented as
=>
=>
Answer:
(a) 0.17 m
(b) 5.003 m
(c) 6.38 × N
(d) 7.37 × N
Explanation:
(a) The minimum value of will occur when q3 = 0 m or at origin and q1, q2 are at 0.17 m so the distance between q3 and q1, q2 is 0.17 m, therefore the <em>minimum value of x= 0.17 m</em>.
(b) The maximum value of x will occur when q3 = 5 m because it is said in the question that 5 is the maximum distance travelled by q3. To find the hypotenuse i.e. the distance between q3 and q1,q2, we use Pythagoras theorem.
<em>Hence, the maximum distance is 5.002 m</em>
(c) For minimum magnitude we use the minimum distance calculated in (a)
Minimum Distance = 0.17 m
For electrostatic force=
×
(d) For maximum magnitude, we use the maximum distance calculated in (b)
Maximum Distance = 5.002 m
Using the formula for electrostatic force again:
F =
F= 7.37× N
Explanation:
V=40m/s
Vy=V.sina=40.sin20=40 . 0.342=13.68m/s
Vx=V.cosa=40.cos20=40 . 0.766=30.64m/s
Projectile travels during 5 seconds and the ramge becomes:
x=V.t=30.64 . 5=153.2m
Answer:
Mass defect of each iron-56 nuclei:
The binding energy per nucleon of Iron-56 is approximately 8.6 MeV.
Explanation:
According to the physics constants table on Chemistry Libretexts:
<h3>a)</h3>
The mass defect of a nucleus is equal to the sum of the mass of its parts (protons and, in most cases, neutrons) minus the mass of the nucleus.
The atomic number of iron is 26. There are 26 protons in each iron-56 nucleus. The mass number 56 indicates that there are 56 nucleons (neutrons and protons) in each iron-56 nucleus. The other particles are neutrons.
The mass of protons and neutrons in each iron-56 nucleus will be:
.
According to this question, the mass of an iron-56 nucleus is equal to 55.934939 amu. The mass defect will be
.
By the mass-energy equivalence,
.
Refer to this equation, the speed of light in vacuum is the conversion factor between mass
and energy
. The value of
is usually given only in SI units
. Accordingly, the value of
will be in the SI unit
.
Convert million electron-volts to joules.
One electron-volt is equal to the electrical work done moving an electron across a potential difference of one volt.
.
Convert the unit of from
to the desired
:
.
Total binding energy in each iron-56 nucleus:
.
Again, the mass number 56 indicates that there are 56 nucleons in each iron-56 nucleus. The binding energy per nucleon of iron-56 will be:
.