The ammonia gas is absorbed in the concentrated brine to produce aqueous sodium chloride and aqueous ammonia. This ammoniation process is exothermic, so energy is released as heat. The ammonia tower eventually needs to be cooled.
Answer is: 73.52 kJ<span> of energy is required to vaporize butane.
</span>m(C₄H₁₀) = 185 g.
n(C₄H₁₀) = m(C₄H₁₀) ÷ M(C₄H₁₀).
n(C₄H₁₀) = 185 g ÷ 58.12 g/mol.
n(C₄H₁₀) = 3.18 mol; amount of butane.
Hvap = 23.1 kJ/mol; <span>the heat of vaporization for butane.
</span>Q = Hvap · n(C₄H₁₀).
Q = 23.1 kJ/mol · 3.18 mol; energy.
Q = 73.52 kJ.
That number, also known as the frequency, will be larger for a short-wavelength wave than for a long-wavelength wave. The equation<span> that relates wavelength and frequency for electromagnetic waves is: λν=c where </span>λ<span> is the wavelength, ν is the frequency and c is the speed of light.</span>
Answer: The atomic weight of the metal would be 85.47.
Explanation:
Mass of isotope 1 of metal = 84.9118
% abundance of isotope 1 of metal = 72.15% = 
Mass of isotope 2 of metal= 86.9092
% abundance of isotope 2 of metal = 27.85% = 
Formula used for average atomic mass of an element :
![A=\sum[(84.9118)\times \frac{72.15}{100})+(86.9092)\times \frac{27.85}{100}]]](https://tex.z-dn.net/?f=A%3D%5Csum%5B%2884.9118%29%5Ctimes%20%5Cfrac%7B72.15%7D%7B100%7D%29%2B%2886.9092%29%5Ctimes%20%5Cfrac%7B27.85%7D%7B100%7D%5D%5D)
Therefore, the atomic weight of the metal would be 85.47.
Answer is: <span>the molarity of the diluted solution 0,043 M.
</span>V(NaOH) = 75 mL ÷ 1000 mL/L = 0,075 L.
c(NaOH) = 0,315 M = 0,315 mol/L.
n(NaOH) = c(NaOH) · V(NaOH).
n(NaOH) = 0,075 L · 0,315 mol/L.
n(NaOH) = 0,023625 mol.
V(solution) = 0,475 L + 0,75 L.
c(solution) = 0,023625 mol ÷ 0,550 L.
c(solution) = 0,043 mol/L.
