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Taya2010 [7]
3 years ago
6

A photographer wants to determine the color of light he can use in the darkroom that will not expose the films he is processing.

In one trial, he used a blue incandescent bulb. Which bulb can he use for another trial?
A. Red incandescent bulb C. Red fluorescent bulb
B. Blue incandescent bulb D. Blue fluorescent bulb
Physics
1 answer:
Sonbull [250]3 years ago
4 0

For a photographer that wishes to determine the color of light that he can use in a dark room that will not expose the films he is processing, having used a Blue Incandescent bulb, he should proceed to use a Red Incandescent bulb for the next trial.

The photographer in question is performing an experiment. For these kinds of experiments it is important to identify the variables present, which can be of three kinds:

  1. Control variables
  2. Dependent variables
  3. Independent variables

For this experiment, the dependent variable is the exposure of the light onto the films, given that this is what we wish to measure. The independent variable will be the color of the light being used which is what will affect the dependent variable.

The remaining variable must be the control variable. Unlike the previous variables, we can have more than one of these. The control variable is there to make sure that only the dependent variable is affecting the outcome. We do this by keeping the control variable the same through each trial, which is why the photographer should not change the type of bulb in the second experiment, changing only the color of the light.

To learn more visit:

brainly.com/question/1549017?referrer=searchResults

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Determine the Mutual Inductance per unit length between two long solenoids, one inside the other, whose radii are r1 and r2 (r2
Triss [41]

Answer:

M' = μ₀n₁n₂πr₂²

Explanation:

Since r₂ < r₁ the mutual inductance M = N₂Ф₂₁/i₁ where N₂ = number of turns of solenoid 2 = n₂l where n₂ = number of turns per unit length of solenoid 2 and l = length of solenoid, Ф₂₁ = flux in solenoid 2 due to magnetic field in solenoid 1 = B₁A₂ where B₁ = magnetic field due to solenoid 1 = μ₀n₁i₁ where μ₀ = permeability of free space, n₁ = number of turns per unit length of solenoid 1 and i₁ = current in solenoid 1. A₂ = area of solenoid 2 = πr₂² where r₂ = radius of solenoid 2.

So, M = N₂Ф₂₁/i₁

substituting the values of the variables into the equation, we have

M = N₂Ф₂₁/i₁

M = N₂B₁A₂/i₁

M = n₂lμ₀n₁i₁πr₂²/i₁

M = lμ₀n₁n₂πr₂²

So, the mutual inductance per unit length is M' = M/l = μ₀n₁n₂πr₂²

M' = μ₀n₁n₂πr₂²

3 0
3 years ago
What type of motion does this graph represent?
Fantom [35]
An object moving with constant velocity
5 0
3 years ago
Use the drop-down menus to identify the type of energy each phrase describes.
Tresset [83]

The shortest wavelength of visible light = violet light

Energy that can be felt as heat but not seen = infrared

Short, invisible rays that can cause eye damage = ultraviolet

Visible light with the longest wavelength = red light

Explanation:

Electromagnetic waves are waves consisting of oscillations of the electric and the magnetic field, occurring in a plane perpendicular to the direction of motion the wave.

They are the only type of waves able to travel without a medium, and they are transverse in nature.

All electromagnetic waves travel in a vacuum at the speed of light, which value is:

c=3.0\cdot 10^8 m/s

Electromagnetic waves are classified into 7 different classes, depending on their wavelength/frequency, and they have different properties. From shortest to longest wavelength (and from highest to lowest frequency), they are:

Gamma rays

X rays

Ultraviolet

Visible light

Infrared radiation

Microwaves

Radio waves

Moreover, the visible light of the spectrum is further divided into different colors, according to how our eye perceive them; from shortest to longest wavelength:

violet

blue

green

yellow

orange

red

Therefore, we have:

  • The shortest wavelength of visible light is violet light, which has wavelength between 380 and 450 nm
  • The longest wavelength of visible light is red light, which has wavelenght between 620 and 750 nm
  • Infrared radiation is a type of radiation that is felt as heat by our body, however it cannot be seen because it falls outside the spectrum of visible light
  • Ultraviolet radiation is also invisible to human eye; it has shorter wavelength than visible light and therefore it has more frequency (and more energy), therefore it can cause damage, especially to the eye

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5 0
3 years ago
Read 2 more answers
A 50kg chandelier hangs from a ceiling suspended by a cable.
babunello [35]

Answer:

The tension force has a magnitude of 490 N, and acts vertically upward

Explanation:

The complete question is:

A 50kg chandelier hangs from a ceiling suspended by a cable. What is the Tension (magnitude and direction of the force) in the cable?

ANS:

Tension is the force applied axially by rope, chain, cable, rod, etc, as a reaction force. The direction of tension is always towards the support. Since, the support here, is ceiling.

Therefore, the direction of tension force will be <u>vertically upward</u><u>.</u>

Since the chandelier is hanging stationary, without any motion. Thus, there must not be any unbalanced force applied on it.

Hence, the tension force must be equal to the weight of chandelier.

Tension Force = Weight of Chandelier

T = W = mg

T = (50 kg)(9.8 m/s²)

<u>T =   490 N</u>

<u>Thus, the tension force has a magnitude of 490 N, and acts vertically upward</u>

6 0
3 years ago
A microwave oven operates at 2.4 GHz with an intensity inside the oven of 2300 W/m2 . Part A What is the amplitude of the oscill
Tasya [4]

Answer:

The amplitude of the oscillating electric field is 1316.96 N/C

Explanation:

Given;

frequency of the wave, f = 2.4 Hz

intensity of the wave, I = 2300 W/m²

Amplitude of oscillating magnetic field is given by;

B_o = \sqrt{\frac{2\mu_o I}{c} }

where;

μ₀ is permeability of free space = 4π x 10⁻⁷ m/A

I is intensity of wave

c is speed of light = 3 x 10⁸ m/s

B_o = \sqrt{\frac{2*4\pi *10^{-7}*2300}{3*10^8} } \\\\B_o = 4.3899 *10^{-6} \ T

The amplitude of the oscillating electric field is given by;

E₀ = cB₀

E₀ = 3 x 10⁸ x 4.3899 x 10⁻⁶

E₀ = 1316.96 N/C

Therefore, the amplitude of the oscillating electric field is 1316.96 N/C

3 0
3 years ago
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