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sladkih [1.3K]
3 years ago
5

As you clear the sidewalk with a leaf blower, the blower pushes you away from the leaves. What is pushing on the blower so that

it can push on you
Physics
1 answer:
iogann1982 [59]3 years ago
4 0

So we want to find what causes the blower to push on you when you use it.

We will see that this happens because of Newton's third law, and the thing that is pushing the blower is the air itself.

Well, Newton's third law says that when two objects interact, they exert equal and opposite forces on each other.

In this case, the leaf blower is interacting with the air, pushing it so it can push away the leaves. But by this law, the air also exerts a force on the leaf blower (we have the interaction leaf blower- air) so the air is what "pushes" the blower, and because you are holding it, you feel that push.

If you want to learn more, you can read:

brainly.com/question/3715235

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As an object increases or decreases, what happens to the total energy?
kompoz [17]

Answer:As an object speeds up, the total energy increases / decreases / remains the same. As an object slows down, the total energy increases / decreases / remains the same.

Explanation:

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3 years ago
Which type of motion most accurately describes the behavior of a friction -less pendulum?
kaheart [24]

Answer:

B) Periodic Motion

Explanation:

When a pendulum is friction-less, i.e there are no damping forces acting on it, its motion will be periodic, i.e it will bob up and down going from potential energy to kinetic energy and back. Thus, the motion of the pendulum can be best described by the term "period motion", hence choice B.

If however, forces do act on the pendulum, and if they acts as to damp the pendulum, it will oscillate less and less as time goes by, and eventually come to a stop (in the real world this damping force is usually air resistance ). And if the force acts in such a way that it increases the oscillations, the pendulum will swing higher and higher, and the system will go haywire! :)

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4 years ago
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8 0
3 years ago
1) Use SolidWorks (SW) FEA to apply a bending load of 600 lbf on the right end of the stepped shaft as shown below. This is the
salantis [7]

Solution :

Given :

L = 1 in

d = 0.75 in

D = 1 in

Fillet radius, r = 0.063 in

$K_{t_{bending}=\frac{\sigma_{FEA_{bending }}}{\sigma_{Nominal_{bending }}}$

We know that :

$\sigma_{b} = \frac{32M}{\pi d^3}$

$\sigma_{b} = \frac{32 \times (2998.63 \times 25.4)}{\pi (0.75 \times 25.4)^3}$

    $=112.27 \ N/mm^2$

$\sigma_{FEA} = 1.3 \times 10^8 \ N/m^2$

         $=1.3 \times 10^8 \times 10^{-6}$

         $=1.3 \times 10^2$   MPa

         = 130 MPa

Therefore, the stress concentration factor is :

$k_t=\frac{130}{112.27}$

   = 1.157922

8 0
3 years ago
When you're 10 or 20 miles away from the origin of an earthquake, the P-waves get to you a little bit before the S-waves. Which
zvonat [6]

Explanation:

P, Primary, or Compressional waves travel the fastest (~6 km/sec in the upper crust). They cause the matter to oscillate forward and backward, parallel to the motion of the seismic wavefront. P waves push (compress) and pull (dilate) the rock that they pass through.

yor answe is (B)

4 0
3 years ago
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