Given:
Stock dose/concentration of 20% Acetylcysteine (200 mg/mL)
150 mg/kg dose of Acetylcysteine
Weight of the dog is 13.2 lb
First we must convert 13.2 lb to kg:
13.2 lb/(2.2kg/lb) = 6 kg
Then we must calculate the dose:
(150 mg/kg)(6kg) = 900 mg
Lastly, we must calculate the dose in liquid form to be administered:
(900 mg)/(200 mg/mL) = 4.5 mL
Therefore, 4.5 mL of 20% Acetylcysteine should be given.
Answer:
Hello There!!
Explanation:
I believe the answer is nuclear.
hope this helps,have a great day!!
~Pinky~
Answer:- Atomic number for sulfur is 16 and it's electron configuration is 
. Here, there are total for electrons in 3p and the set of quantum numbers for these 4 electrons would be as..
For the first electron of 3p-
n = 3, l = 1, ml = -1 and ms = +(1/2)
for the second electron of 3p-
n = 3, l = 1, ml = 0 and ms = +(1/2)
for the third electron of 3p-
n = 3, l = 1, ml = +1 and ms = +(1/2)
and for the fourth electron of 3p-
n = 3, l = 1, ml = -1 and ms = -(1/2)
Answer:
2nd option is NOT a postulate of kinetic theory of gases
Explanation:
actually particles move in straight random motion and create bombardment with the molecules and container
Answer is: n<span>o, because the ion product is less than the Ksp of lead iodide. </span>
Chemical dissociation 1: KI(s) → K⁺(aq) + I⁻(aq).
Chemical dissociation 2: Pb(NO₃)₂(s) → Pb²⁺(aq) + 2NO₃⁻(aq).
Chemical reaction: Pb²⁺(aq) + 2I⁻(aq) → PbI₂(s).
Ksp(PbI₂) = 7.1·10⁻⁹.
V = 500 mL ÷ 1000 mL/L = 0.5 L.
c(KI) = c(I⁻) = 0.0025 mol ÷ 0.5 L.
c(I⁻) = 0.005 M.
c(Pb(NO₃)₂) = c(Pb²⁺) = 0.00004 mol ÷ 0.5 L.
c(Pb²⁺) = 0.00008 M.
Q = c(Pb²⁺) · c(I⁻)².
Q = 8·10⁻⁵ M · (5·10⁻³ M)².
Q = 2·10⁻⁹; <span> the ion product.</span>
